使用排序函数对列表的嵌套列表进行排序。？

Question

我有一张名单叫myList。我想实现的是，我想根据age key的值对列表进行排序。我知道可以用排序函数来完成，但我不知道如何为键编写函数。任何人都可以向我提出解决问题的办法。你知道吗

myList = [ {'john':{'age':30 ,'salary':600000}}, {'mullar':{'age':25 ,'salary':250000}},
           {'todd':{'age':40 ,'salary':300000}},{'rolex':{'age':20 ,'salary':450000}},
           {'ron':{'age':20 ,'salary':500000}},{'gilex':{'age':30 ,'salary':450000}},
           {'larrat':{'age':41 ,'salary':350000}},{'fyoid':{'age':24 ,'salary':400000}},
           {'devon':{'age':33 ,'salary':600000}},{'dron':{'age':20 ,'salary':200000}}
         ]

Answer 1

def getAge(d):
  salary = list(d.values())[0]['age']
  return salary



#d.values() => dict_values([{'age': 30, 'salary': 600000}])
#list(d.values()) => [{'age': 30, 'salary': 600000}]
#list(d.values())[0] => {'age': 30, 'salary': 600000}
##list(d.values())[0]['age'] => 30
print(sorted(myList,key=getAge))

结果

[{'rolex': {'age': 20, 'salary': 450000}}, {'ron': {'age': 20, 'salary': 500000}}, {'dron': {'age': 20, 'salary': 200000}}, {'fyoid': {'age': 24, 'salary': 400000}}, {'mullar': {'age': 25, 'salary': 250000}}, {'john': {'age': 30, 'salary': 600000}}, {'gilex': {'age': 30, 'salary': 450000}}, {'devon': {'age': 33, 'salary': 600000}}, {'todd': {'age': 40, 'salary': 300000}}, {'larrat': {'age': 41, 'salary': 350000}}]