<p>下面是一些让您开始的内容(您可能希望将循环一行分隔为较小的位):</p>
<pre><code># define data
data = [['B', 'C', 'D', 'E'], ['D', 'E', 'D', 'A'], ['F', 'D', 'D', 'D'], ['B', 'E', 'F', 'E'], ['D', 'A', 'E', 'A'], ['F', 'E', 'B', 'C']]
# choose code word
code = 'code'
# add original locations to code word [(0, c), (1, o), (2, d), (3, e))]
# and sort them alphabetically!
code_with_locations = list(sorted(enumerate(code)))
print code_with_locations # [(0, 'c'), (2, 'd'), (3, 'e'), (1, 'o')]
# re-organize data according to new indexing
for index in range(len(data)):
# check if code is shorter than list in current index,
# or the other way around, don't exceed either list
max_substitutions = min(map(len, [code_with_locations, data[index]]))
# create a new list according to new indices
new_list = []
for i in range(max_substitutions):
current_index = code_with_locations[i][0]
new_list.append(data[index][current_index])
# replace old list with new list
data[index] = new_list
print data
</code></pre>
<p>“代码”的输出为:</p>
<pre><code>[['B', 'D', 'E', 'C'],
['D', 'D', 'A', 'E'],
['F', 'D', 'D', 'D'],
['B', 'F', 'E', 'E'],
['D', 'E', 'A', 'A'],
['F', 'B', 'C', 'E']]
</code></pre>