擅长:python、mysql、java
<p>您可以使用如下循环遍历对:</p>
<pre><code>for prv, nxt in zip(ls[:-1], ls[1:]):
...
</code></pre>
<p>例如:</p>
<pre><code>ls = [
'request1',
'request2',
'request3',
'response3',
'request4',
'response4',
]
for prv, nxt in zip(ls[:-1], ls[1:]):
if 'request' in prv and 'response' in nxt:
print prv, nxt
</code></pre>