擅长:python、mysql、java
<p>你可以用<code>re.findall</code></p>
<pre><code>>>> s = 'ArcelorMittal invests =E2=82=AC87m in new process that cuts emissions=20'
>>> re.findall(r'(?:=\w{2})+', s)
['=E2=82=AC', '=20']
>>>
</code></pre>
<p>如果要删除这些字符,请使用<code>re.sub</code>。你知道吗</p>
<pre><code>>>> re.sub(r'(?:=\w{2})+', '', s)
'ArcelorMittal invests 87m in new process that cuts emissions'
</code></pre>