为什么这个CSV转换会作为一个元素返回到每个数组元素中

Question

到目前为止，我尝试的是：

import csv
print "Dennis"
with open('Example1.csv', 'rb') as csvfile: 
    dialect = csv.Sniffer().sniff(csvfile.read(1024))
    csvfile.seek(0)
    reader = csv.reader(csvfile, dialect)
    # ... process CSV file contents here ...
    print reader
    try:
        for row in reader:
            #print row
            print row[0],   row[1],   row[2]    #FAILS HERE
    except csv.Error as e:
        #skip

print "ended"

CSV lib似乎转换并打包转换后的数据，如下所示。你知道吗

['GB0002875804,ABIH RIAN TCO ORD,"191,560.00000"']
['GB0002374006,DIO ORD 28 101/108P,"440,274.00000"']
['GB00B03MLX29,ROY DUH ELL PLC,"310,437.00000"']

这类似于单个元素中的多个元素和单个数组元素中的单个元素。有什么好处？你知道吗

我希望得到如下转换。你知道吗

[GB0002875804,ABIH RIAN TCO ORD,"191,560.00000"]
[GB0002374006,DIO ORD 28 101/108P,"440,274.00000"]
[GB00B03MLX29,ROY DUH ELL PLC,"310,437.00000"]

这样我必须提取单个元素，然后提取分离的值。第二种方式是直接转换我想要的数据包中有没有一个以上的例子？你知道吗

非常感谢

丹尼斯

Answer 1

使用csvsniffer会混淆csv读取器。结果是整行没有被分成1个元素的列表。然后，当您尝试打印（访问）不存在的row元素时，会出现索引错误。你知道吗

只需使用默认值并手动删除第一个元素中的['，以及最后一个元素中的逗号和']。我的代码假设没有前导或尾随空格；去掉它们。你知道吗

所以，有了这个文件：

$ cat /tmp/dennis.csv
['GB0002875804,ABIH RIAN TCO ORD,"191,560.00000"']
['GB0002374006,DIO ORD 28 101/108P,"440,274.00000"']
['GB00B03MLX29,ROY DUH ELL PLC,"310,437.00000"']
['GB0008762899,BG GP PC OD G0.10,"486,049.00000"']
['GB0008762899,BG GUP C ORD P0.10,"504,867.00000"']
['GB0005405286,BC HL OR D0.50 (K),"1,751,079.00000"']
['GB0009252882,GAITHNE OD P0.25,"806,535.00000"']
['GB00B16GWD56,VNE GRP,"7,254,981.00000"']

这解决了你的问题（据我所知）：

import csv

LoL=[]
with open('/tmp/Dennis.csv', 'rb') as csvfile:
    reader = csv.reader(csvfile)
    try:
        for row in reader:
            row[0]=row[0].replace("['","")
            row[2]=float(row[2].replace("']","").replace(',',''))
            LoL.append(row)
            print ''.join('{}[{}]:{} '.format('row',i,e) for i,e in enumerate(row))

    except (csv.Error, ValueError) as e:
        print 'something bad happened...\ndying now...\n',e

print LoL

印刷品：

row[0]:GB0002875804 row[1]:ABIH RIAN TCO ORD row[2]:191560.0 
row[0]:GB0002374006 row[1]:DIO ORD 28 101/108P row[2]:440274.0 
row[0]:GB00B03MLX29 row[1]:ROY DUH ELL PLC row[2]:310437.0 
row[0]:GB0008762899 row[1]:BG GP PC OD G0.10 row[2]:486049.0 
row[0]:GB0008762899 row[1]:BG GUP C ORD P0.10 row[2]:504867.0 
row[0]:GB0005405286 row[1]:BC HL OR D0.50 (K) row[2]:1751079.0 
row[0]:GB0009252882 row[1]:GAITHNE OD P0.25 row[2]:806535.0 
row[0]:GB00B16GWD56 row[1]:VNE GRP row[2]:7254981.0 
[['GB0002875804', 'ABIH RIAN TCO ORD', 191560.0], ['GB0002374006', 'DIO ORD 28 101/108P', 440274.0], ['GB00B03MLX29', 'ROY DUH ELL PLC', 310437.0], ['GB0008762899', 'BG GP PC OD G0.10', 486049.0], ['GB0008762899', 'BG GUP C ORD P0.10', 504867.0], ['GB0005405286', 'BC HL OR D0.50 (K)', 1751079.0], ['GB0009252882', 'GAITHNE OD P0.25', 806535.0], ['GB00B16GWD56', 'VNE GRP', 7254981.0]]

Answer 2

你不需要把这些列也写一遍吗？即：

for row in reader:
          for col in row:
            print  col