当我试图修复我的urlpatterns
中的url时,它会显示以下错误:
错误:
Your URL pattern "url(r'^player/[?P[-\w\x20]+]/$', PlayerDetailView.as_view(), name='player-detail-view')," is invalid. Ensure that urlpatterns is a list of url() instance. try removing the string 'url(r'^player/[?P[-\w\x20]+]/$', PlayerDetailView.as_view(), name='player-detail-view'),'. The list of urlpatterns should not have a prefix string as the first element.*
我的代码:
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^$', HomePageView.as_view(), name='home-page'),
url(r'^teams/$', TeamsListView.as_view(), name='teams-list-view'),
url(r'^scores/$', ScoresListView.as_view(), name='scores-list-view'),
url(r'^player/[?P<slug>[-\w\x20]+]/$', PlayerDetailView.as_view(), name='player-detail-view'),
]
有人能帮我吗??你知道吗
语法有点错误,您需要在“捕获组”周围使用圆形方括号
(..)
,而不是方形方括号[..]
:此外,如果我没记错的话,slug不能包含空格,因此您可能需要删除
\x20
。你知道吗请注意,在django-2.0及更高版本中,可以使用^{} [Django-doc]函数,它支持slug,如:
然后Django用一个内置模式替换slug,这使得URL模式更加“声明性”。你知道吗
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