如何为字符串列表中的一个字符串获取一个语法集？

Question

我试图在列表中找到字符串的语法集。我的代码是：

from nltk.corpus import wordnet as wn
from nltk import pos_tag

word1 =  ['orange','man','bench']

def getSynonyms(word1):
    synonymList1 = []
    for data1 in word1:
        wordnetSynset1 = wn.synsets(data1)
        tempList1=[]
        for synset1 in wordnetSynset1:
            synLemmas = synset1.lemma_names()
            for i in xrange(len(synLemmas)):
                word = synLemmas[i].replace('_',' ')
                if pos_tag(word.split()) not in tempList1:
                    tempList1.append(pos_tag(word.split()))
        synonymList1.append(tempList1)
    return synonymList1

print getSynonyms(word1)
print

结果如下：

^{pr2}$

但是如果我只想得到一个字符串的synsets呢？在

例如，如果我得到'orange'的synsets，我将只获取并打印：

[(u'orange', 'NN')], [(u'orangeness', 'NN')], [(u'orange', 'NN'), 
(u'tree', 'NN')], [(u'Orange', 'NN')], [(u'Orange', 'NNP'), (u'River', 
'NNP')], [(u'orangish', 'JJ')]

如果我得到'man'的语法集，我将只获取并打印：

[(u'man', 'NN')], [(u'adult', 'NN'), 
(u'male', 'NN')], [(u'serviceman', 'NN')], [(u'military', 'JJ'), (u'man', 
'NN')], [(u'military', 'JJ'), (u'personnel', 'NNS')], [(u'homo', 'NN')], 
[(u'human', 'JJ'), (u'being', 'VBG')], [(u'human', 'NN')], [(u'valet', 
'NN')], [(u'valet', 'NN'), (u'de', 'IN'), (u'chambre', 'NN')], 
[(u'gentleman', 'NN')], [(u"gentleman's", 'NN'), (u'gentleman', 'NN')], 
[(u'Man', 'NN')], [(u'Isle', 'NNP'), (u'of', 'IN'), (u'Man', 'NNP')], 
[(u'piece', 'NN')], [(u'world', 'NN')], [(u'human', 'JJ'), (u'race', 'NN')], 
[(u'humanity', 'NN')], [(u'humankind', 'NN')], [(u'human', 'JJ'), 
(u'beings', 'NNS')], [(u'humans', 'NNS')], [(u'mankind', 'NN')]

'bench'也是如此

我试过print getSynonyms(word1[0])，但结果真的很奇怪。在

有人能帮忙吗？谢谢

Answer 1

这个函数需要一个数组，这就是为什么传递一个字符串会得到奇怪的结果。如果你给它传递一个单词，它会为单词的每个字母查找语法集。但是，您可以传递一个包含一个值的数组：

print getSynonyms([word1[0]])

您还可以重写该函数以删除out循环，从而允许您通过类似以下内容传入单个单词：

^{pr2}$