擅长:python、mysql、java
<p>你的实现有两个错误。首先,<code>get_film</code>。这个方法中的参数是错误的。你需要这样定义它:</p>
<pre><code>@api_view(['GET', 'POST'])
def get_film(request, id): # < First argument is request which is for `HttpRequest` object. Second is `id` which is for mapping it with the url's id.
print('entered')
request_url = API_URL + "films/" + str(id)
# rest of the code
</code></pre>
<p>第二,当调用这个<strong>api</strong>时,您需要这样做:<code>http://127.0.0.1:8000/api/films/4/</code></p>