是否可以合并两个集合，使所有对两个集合的引用都引用新的集合？

Question

在Python中，假设我有两个集合A和B，以及对这两个集合的多个引用。在

是否有方法合并a和B两个集合，使得对这两个集合的所有引用都将引用新合并的集合？如果可能，运行时间是什么？在

A = {1,3}
B = {2,4}
aRef1 = A
aRef2 = A
bRef1 = B
bRef2 = B
MergeSets(A,B)
# Now, whenever I use any of (A, B, aRef1, aRef2, bRef1, bRef2) 
# they refer to the same set which will be {1,2,3,4} 

谢谢你

编辑：

有人一直在问我为什么要这么做，下面是我的一个回复的复制/粘贴：

So I know I can do A.update(B), to merge B into A, but then I'd have to iterate through all references to B and set them to refer to A. I was asking so I can avoid these extra iterations. I could supply more context to get a new approach to my specific scenario, but I'm more curious to know if this is possible in python as a general case.

此外，我的问题似乎已经得到了回答，而结论是这是不可能的。再次感谢大家：）

Answer 1

将参数作为引用传递给函数，因此不能将参数作为参数传递给函数。另一种方法是改变传递给函数的对象。在

In [35]: A = {1,3}
    ...: B = {2,4}
    ...: aRef1 = A
    ...: aRef2 = A
    ...: bRef1 = B
    ...: bRef2 = B

In [36]: def merge_sets(a, b):
    ...:     for el in b:
    ...:         a.add(el)
    ...:     for el in a:
    ...:         b.add(el)

In [37]: merge_sets(A, B)

In [38]: [id(s) for s in (A, B, aRef1, aRef2, bRef1, bRef2)]
Out[38]:
[140333907731848,
 140333907731176,
 140333907731848,
 140333907731848,
 140333907731176,
 140333907731176]

In [39]: [s for s in (A, B, aRef1, aRef2, bRef1, bRef2)]
Out[39]:
[{1, 2, 3, 4},
 {1, 2, 3, 4},
 {1, 2, 3, 4},
 {1, 2, 3, 4},
 {1, 2, 3, 4},
 {1, 2, 3, 4}]

merge_sets以线性时间执行。在