擅长:python、mysql、java
<p>可以使用Counter对象按字母计数对单词进行分组:</p>
<pre><code>from collections import Counter
from itertools import groupby
sorted list = sorted(anList, key=Counter)
groups = [list(y) for x, y in groupby(sortedList, key=Counter)]
#[['aba', 'baa', 'aab'], ['cat', 'tac', 'act'], ['sos', 'oss']]
</code></pre>
<p>现在,将字谜列表转换成字典:</p>
^{pr2}$