擅长:python、mysql、java
<p>检查一下,告诉我:</p>
<pre><code>text = "xxxxAAaaaSSSxxx"
PasswordSubHT = {"a":"@" , "A":"4" , "S":"5"}
for letter in text:
if letter in PasswordSubHT.keys():
text = text.replace(letter, str(PasswordSubHT[letter]))
print(text)
</code></pre>
<p>注意:<br/>
<code>replace(x, y)</code>将替换文本中的所有<code>x</code>。如果您想一次只替换一个字符,请添加<code>count</code>参数=1:<code>text = text.replace(letter, str(PasswordSubHT[letter]), 1)</code></p>