要从配对中删除lis时出现问题

Question

我有一段代码允许用户删除已经在线索列表中的配对。但是当我尝试运行这段代码时，出现了一个错误，我不确定如何解决这个问题。。。 删除配对的位的代码如下所示。。。在

def delete_pairing(clues):
    found = True
    #USER INPUTS A LETTER AND SYMBOL
    letter=input("What letter would you like to delete? ").upper
    symbol=input("\nWhat symbol would you like to delete? ")
    #THE LETTER AND SYMBOL THE USER INPUTS BECOMES ONE STRING
    delClue = letter + symbol
    #IF THE delClue exists in clues, it will delete the pairing
    if delClue in clues:
    #CODE FOR REMOVING THE CLUE
        clues.remove(delClue)
    # LETS THE USER KNOW WHAT CLUES HAS BEEN DELETED
        print("\nClue ",(delClue)," has been deleted")
        print("\nYour clues are now...")
        print (clues)
    #If delClue doesn't exist in clues, it will print an error message    
    else:
        print("That clue does not exist  ")
    return clues

结果应该是，如果用户输入的字母和符号配对在线索列表中，那么它应该被删除。否则，会出现一条错误消息，说明用户输入的字母和符号配对不在线索列表中。。。。在

我犯的错误。。。在

^{pr2}$

Answer 1

正如the comment of Ashwini Chaudhary所述，您忘记了()在这一行的末尾

letter=input("What letter would you like to delete? ").upper

因此letter不是您所期望的string类型，而是一个builtin_function_or_method（即^{} method of python's string type）。这就是你不能把它连接到另一个字符串的方式。在