带有.NET路由器的高速公路组件（WampSharp）

Question

现在我在玩WAMP proto，我很好奇这样的事情是否可能，因为我无法让它工作：

1.使用c#（WampSharp）编写WAMP路由器：

const string location = "ws://127.0.0.1:9999/wsdemo";

try
{
    using (IWampHost host = new DefaultWampHost(location))
    {
        IWampHostedRealm realm = host.RealmContainer.GetRealmByName("realm1");
        host.Open();
        Console.WriteLine("Host is running on : " + location);
    }
}
catch(Exception exc)
{
    Console.WriteLine("Error : " + exc.ToString());
}

2.使用python编写组件：

^{pr2}$

当我运行python脚本时，我得到一个错误：

2017-02-20T19:49:46+0100 Main loop terminated.
2017-02-20T19:49:46+0100 Traceback (most recent call last):
2017-02-20T19:49:46+0100   File "C:\Program Files (x86)\JetBrains\PyCharm Educational Edition 1.0.1\helpers\pydev\pydevd.py", line 2199, in <module>
2017-02-20T19:49:46+0100     globals = debugger.run(setup['file'], None, None)
2017-02-20T19:49:46+0100   File "C:\Program Files (x86)\JetBrains\PyCharm Educational Edition 1.0.1\helpers\pydev\pydevd.py", line 1638, in run
2017-02-20T19:49:46+0100     pydev_imports.execfile(file, globals, locals)  # execute the script
2017-02-20T19:49:46+0100   File "D:/Programming/Astronomy/Dev/ZenithPlatform/backbone/local/tests/wamp.py", line 41, in <module>
2017-02-20T19:49:46+0100     runner.run(Component)
2017-02-20T19:49:46+0100   File "C:\Python27\lib\site-packages\autobahn\twisted\wamp.py", line 312, in run
2017-02-20T19:49:46+0100     raise connect_error.exception
2017-02-20T19:49:46+0100 twisted.internet.error.ConnectionRefusedError: Connection was refused by other side: 10061: No connection could be made because the target machine actively refused it..

根据http://autobahn.ws/python/wamp/programming.html#running-a-wamp-router

The component we’ve created attempts to connect to a WAMP router running locally which accepts connections on port 8080, and for a realm realm1.

Our suggested way is to use Crossbar.io as your WAMP router. There are other WAMP routers besides Crossbar.io as well.

这样的事情到底能实现吗？在

谢谢，
Civa公司

Answer 1

你的using语句在程序结束前处理路由器。在

只需添加一个控制台.ReadLine（）；语句位于控制台.WriteLine（）声明。那应该行得通。在