hand = ['A','Q']
points = 0
player_cards1 = ['2']
value1 = 2
player_cards2 = ['3']
value2 = 3
player_cards3 = ['4']
value3 = 4
player_cards4 = ['5']
value4 = 5
player_cards5 = ['6']
value5 = 6
player_cards6 = ['7']
value6 = 7
player_cards7 = ['8']
value7 = 8
player_cards8 = ['9']
value8 = 9
player_cards9 = ['T']
value9 = 10
player_cards10 = ['Q']
value10 = 10
player_cards11 = ['K']
value11 = 10
player_cards12 = ['J']
value12 = 10
ACE11 = ['A']
value13 = 11
for hand in player_cards1:
flag = True
if flag == True:
points = points + value1
for hand in ACE11:
flag = True
if flag == True:
points = points + value13
for hand in player_cards2:
flag = True
if flag == True:
points = points + value2
for hand in player_cards3:
flag = True
if flag == True:
points = points + value3
for hand in player_cards4:
flag = True
if flag == True:
points = points + value4
for hand in player_cards5:
flag = True
if flag == True:
points = points + value5
for hand in player_cards6:
flag = True
if flag == True:
points = points + value6
for hand in player_cards7:
flag = True
if flag == True:
points = points + value7
for hand in player_cards8:
flag = True
if flag == True:
points = points + value8
for hand in player_cards9:
flag = True
if flag == True:
points = points + value9
for hand in player_cards10:
flag = True
if flag == True:
points = points + value10
for hand in player_cards11:
flag = True
if flag == True:
points = points + value11
for hand in player_cards12:
flag = True
if flag == True:
points = points + value12
print points
它在前五个街区跑得很好,然后它给了我整副牌的总价值(95)。我怎么解决这个问题?它应该只给我手上牌的价值。我在这里做错了什么?在
编辑以使答案更具教学性。
使用^{} 存储每张卡片的分数。在
然后,您可以在
hard
中的每个card
进行迭代,在字典中查找其值,并将分数相加,得出总数。在您可能想看看^{} 函数,它在这里可能很有用。在
你的台词:
很可能没有做你期望的事情。看起来你认为它会比较hand和player_cards1;相反,它所做的是在player_cards1上创建一个迭代器,您可以通过变量hand访问该迭代器(意味着hand被重新分配,不再是['A','Q'])。下面是一个简单的例子:
^{pr2}$三行程序将输出:
取而代之的是,你可能需要在手中的卡片上进行迭代,例如:
^{4}$我也建议你重新考虑一下你追踪信用卡价值的方式,因为这会非常麻烦。提示:只有少数情况下你不能使用信用卡的面值。在
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