擅长:python、mysql、java
<p>如果只想检查列表中任何字符串中是否存在<code>"goodTime99"</code>,可以尝试:</p>
<pre><code>value = ["python:guru-age20", "is_it_possible_time100:goodTime99","hmm_hope_no_onecanansswer"]
if any("goodTime99" in s for s in value):
# found it
</code></pre>
<p>如果您需要确切的位置:</p>
^{pr2}$
<p>或者:</p>
<pre><code>def find_first_substring(lst, substring):
return next((i for i, s in enumerate(lst) if substring in s), -1)
>>> find_first_substring(value, "goodTime99")
1
</code></pre>