Python的关于芬德尔（）函数无法按预期工作

Question

我正在尝试创建一个python脚本，它将从具有特定名称模式的工作目录中查找所有文件。在

我已经将所有文件存储在一个列表中，然后我尝试应用关于芬德尔方法获取具有该名称模式的文件列表。在

我写了以下代码：

# Create the regex object that we will use to find our files
fileRegex = re.compile(r'A[0-9]*[a-z]*[0-9]*.*')
all_files = []

# Recursevly read the contents of the working_dir/Main folder #:
for folderName, subfolders, filenames in os.walk(working_directory + "/Main"):
    for filename in filenames:
        all_files.append(filename)

found_files = fileRegex.findall(all_files)

我在代码的最后一行得到了这个错误：

^{pr2}$

我也试过了关于芬德尔（所有_文件）而不是使用在该行之前创建的“fileRegex”。同样的错误。请告诉我我做错了什么。非常感谢您阅读我的帖子！在

编辑（第二个问题）： 我已经找到了答案，现在一切正常。我正在尝试创建一个档案，其中的文件与我找到的模式相匹配。存档是以我编写代码的方式创建的，文件的整个路径都包含在归档文件中（从文件到文件的所有文件夹）。我只希望文件包含在final.zip文件中，而不是创建路径的整个目录和子目录。在

这是密码。.zipfile的生成位于底部。请给我一个提示，我该怎么解决这个问题我试了很多方法，但都没用。谢谢：

# Project properties:

#  Recursively read the contents of the 'Main' folder which contains files with different names.
#  Select only the files whose name begin with letter A and contain digits in it. Use regexes for this.
#  Archive these files in a folder named 'Created_Archive' in the project directory. Give the archive a name of your choosing.


# Files that you should find are:
  # Aerials3.txt, Albert0512.txt, Alberto1341.txt


########################################################################################################################################
import os
import re
import zipfile
from pathlib import Path

# Get to the proper working directory
working_directory = os.getcwd()
if working_directory != "/home/paul/Desktop/Python_Tutorials/Projects/Files_And_Archive":
  working_directory = "/home/paul/Desktop/Python_Tutorials/Projects/Files_And_Archive"
  os.chdir(working_directory)

check_archive = Path(os.getcwd() + "/" + "files.zip")
if check_archive.is_file():
    print("Yes. Deleting it and creating it.")
    os.unlink(os.getcwd() + "/" + "files.zip")
else:
    print("No. Creating it.")

# Create the regex object that we will use to find our files
fileRegex = re.compile(r'A[0-9]*[a-z]*[0-9]+.*')
found_files = []

# Create the zipfile object that we will use to create our archive
fileArchive = zipfile.ZipFile('files.zip', 'a')

# Recursevly read the contents of the working_dir/Main folder #:
for folderName, subfolders, filenames in os.walk(working_directory + "/Main"):
    for filename in filenames:
        if fileRegex.match(filename):
            found_files.append(folderName + "/" + filename)

# Check all files have been found and create the archive. If the archive already exists
# delete it.


for file in found_files:
    print(file)
    fileArchive.write(file, compress_type=zipfile.ZIP_DEFLATED)

fileArchive.close()

Answer 1

^{}处理的是字符串而不是列表，因此最好在列表上使用^{}来筛选实际匹配的字符串：

found_files = [s for s in all_files if fileRegex.match(s)]

Answer 2

^{}不接受字符串列表。你需要^{}。在

# Create the regex object that we will use to find our files
fileRegex = re.compile(r'A[0-9]*[a-z]*[0-9]*.*')
all_files = []

# Recursively read the contents of the working_dir/Main folder #:
for folderName, subfolders, filenames in os.walk(working_directory + "/Main"):
    for filename in filenames:
        all_files.append(filename)

found_files = [file_name for file_name in all_files if fileRegex.match(file_name)]

Answer 3

regex用于字符串而不是列表。以下工作

import re
import os

# Create the regex object that we will use to find our files
# fileRegex = re.compile(r'A[0-9]*[a-z]*[0-9]*.*')
fileRegex = re.compile(r'.*\.py')
all_files = []
found_files = []

working_directory = r"C:\Users\michael\PycharmProjects\work"

# Recursevly read the contents of the working_dir/Main folder #:
for folderName, subfolders, filenames in os.walk(working_directory):
    for filename in filenames:
        all_files.append(filename)
        if fileRegex.search(filename):
            found_files.append(filename)

print('all files\n', all_files)
print('\nfound files\n', found_files)