擅长:python、mysql、java
<p>这里有一个单一的解决方案</p>
<pre><code>>>> t = [ ('wanna', 'o'),
... ('be', 'o'),
... ('like', 'o'),
... ('Alexander', 'B'),
... ('Coughan', 'I'),
... ('?', 'o')]
>>> x = [B[0] for B in t if B[1]=='B'][0] + ' ' + [I[0] for I in t if I[1]=='I'][0]
>>> print x
Alexander Coughan
>>>
</code></pre>