<p>使用OrderedDict和元组列表来设置初始顺序怎么样。然后简单地维护它。在</p>
<p>请检查我的答案以获得更好的dict语法:<a href="https://stackoverflow.com/questions/7878933/is-possible-to-override-the-notation-so-i-get-an-ordereddict-instead-of/25889274#25889274">Override the {...} notation so i get an OrderedDict() instead of a dict()?</a></p>
<pre><code>from collections import OrderedDict
#Use an ordered dict, with a tuple list init to maintain initial order
a = OrderedDict([
(u'Anthracite', [u'3/optimized/8593793_fpx.tif']),
(u'Black', [u'6/optimized/8593796_fpx.tif']),
(u'Cobalt', [u'9/optimized/8593799_fpx.tif']),
(u'Fire', [u'2/optimized/8593802_fpx.tif']),
(u'Fuschia', [u'5/optimized/8593805_fpx.tif']),
(u'Iris', [u'8/optimized/8593808_fpx.tif']),
(u'Midnight', [u'1/optimized/8593811_fpx.tif'])
])
#We don't care about b's order
b = {u'Anthracite': [u'5/optimized/8593795_fpx.tif'],
u'Black': [u'8/optimized/8593798_fpx.tif'],
u'Cobalt': [u'1/optimized/8593801_fpx.tif'],
u'Fire': [u'4/optimized/8593804_fpx.tif'],
u'Fuschia': [u'7/optimized/8593807_fpx.tif'],
u'Iris': [u'0/optimized/8593810_fpx.tif'],
u'Midnight': [u'3/optimized/8593813_fpx.tif']}
merge = OrderedDict()
#Since b has the same keys as a(we don't need to care for diffrent keys), but we want a's order
for key in a:
#We insert by order to an OrderedDict so the same order will be maintained
merge[key] = a[key] + b[key]
</code></pre>