擅长:python、mysql、java
<p>我想你不需要用params。只需格式化一个URL就足够了。像这样:</p>
<pre><code># -*- coding: utf-8 -*-
#!/usr/bin/python
import requests
symbol = raw_input("Symbol: ")
params = (symbol, '00', '11', '2010', '00', '13', '2010')
url = 'http://finance.yahoo.com/q/hp?s=%s&a=%s&b=%s&c=%s&d=%s&e=%s&f=%s&g=d' % params
response = requests.get(url)
# you will get 200 OK here
print response
# and page info is in response.text
</code></pre>