在Python（2.7）中按周存储工作日？

Question

我如何创建一个Python脚本来存储任何月份的工作日日期及其对应的周数？在

这个问题令人困惑，所以这里有一个“视觉”：

August_2013 = {
  ( week1 : (8/1/2013),  (8/2/2013) ),
  ( week2 : (8/5/2013),  (8/6/2013),  (8/7/2013),  (8/8/2013),  (8/9/2013)  ),
  ( week3 : (8/12/2013), (8/13/2013), (8/14/2013), (8/15/2013), (8/16/2013) ),
  ( week4 : (8/19/2013), (8/20/2013), (8/21/2013), (8/22/2013), (8/23/2013) ),
  ( week5 : (8/26/2013), (8/27/2013), (8/28/2013), (8/29/2013), (8/30/2013) )
}

通过搜索所有的SO，我编写了以下代码来计算两天之间的工作日数：

^{pr2}$

但是这些代码还不够。。我需要知道每个月的哪个星期有多少个工作日。在

编辑：我的操作系统是Windows7。我使用的是python2.7。在

Answer 1

import calendar
import collections
from datetime import date

def get_weeks(year, month, holidays):
    cal = calendar.Calendar(0)
    weeks = collections.defaultdict(lambda: 0)
    for i, week in enumerate(cal.monthdatescalendar(year, month)):
        # Get just mon-fri
        for day in week[:-2]:
            if day.month == month and day not in holidays:
                weeks['week%s' % (i+1)] += 1
    return weeks
holidays = [date(2013, 8, 2), date(2013, 8, 6)]
print get_weeks(2013, 8, holidays)

这给了我：

^{pr2}$

如果我在8月29日再增加一个假期，我将得到：

>>> holidays = [date(2013, 8, 2), date(2013, 8, 6), date(2013, 8, 29)]
>>> print  get_weeks(2013, 8, holidays)
{'week2': 4, 'week1': 1, 'week4': 5, 'week3': 5, 'week5': 4})

更新：

import calendar
import collections
from datetime import date

def get_weeks(year, month, holidays):
    cal = calendar.Calendar(0)
    weeks = collections.defaultdict(list)
    for i, week in enumerate(cal.monthdatescalendar(year, month)):
        # Get just mon-fri
        for day in week[:-2]:
            if day.month == month and day not in holidays:
                weeks['week%s' % (i+1)].append(day)
    return weeks
holidays = [date(2013, 8, 2), date(2013, 8, 6), date(2013, 8, 29)]
print get_weeks(2013, 8, holidays)

这给了我：

{
  'week1': [date(2013, 8, 1)],
  'week2': [date(2013, 8, 5), date(2013, 8, 7), date(2013, 8, 8),
            date(2013, 8, 9)],
  'week3': [date(2013, 8, 12), date(2013, 8, 13), date(2013, 8, 14),
            date(2013, 8, 15), date(2013, 8, 16)],
  'week4': [date(2013, 8, 19), date(2013, 8, 20), date(2013, 8, 21),
            date(2013, 8, 22), date(2013, 8, 23)],
  'week5': [date(2013, 8, 26), date(2013, 8, 27), date(2013, 8, 28),
            date(2013, 8, 30)]

}