擅长:python、mysql、java
<p>试试这个</p>
<pre><code>df['Numbers'].apply(lambda x: x.split('/')[2]), This splits the Dataframe (all rows) for every occurrence of '/' and then takes the value between 2nd and 3rd '/'.
</code></pre>
<p>如果包含意外格式</p>
^{pr2}$
<p>这是用于检查是否正常,如果拆分后列表不包含4个元素,则它将填充“”为空,而不是抛出超出绑定的索引错误。</p>