我在python中有一个AWS Lambda函数,它使用SSM在EC2实例中运行脚本。执行后的脚本在S3(随机名称)中创建一个文件夹。创建文件夹后,lambda函数需要返回一个带有S3文件夹名称的响应。在
当我检查Cloudwatch日志时,我可以在其中一个事件中看到文件夹的名称。但是Lambda函数在所有事件运行之前返回200。在返回响应/200之前,如何使处理程序等待所有事件完成?在
import boto3
import time
def lambda_handler(event, context):
print('event is: ', event)
if 'number' in event.keys():
command = 'python lambda_test.py ' + str(event['number']);
workingDirectory = '/home/ubuntu/src';
executionTimeout = "3600";
ssm = boto3.client('ssm');
ssmresponse = ssm.send_command(InstanceIds=['I-***********a1'], DocumentName='AWSLambdaSampleRun', Parameters= { 'commands': [command], 'workingDirectory': [workingDirectory], 'executionTimeout' : [executionTimeout] }, ServiceRoleArn='arn:aws-us-west-1:sts::***************:assumed-role/lambda/sample', OutputS3BucketName = 'sample-ui' )
records = [x for x in event.get('Records', []) if x.get('eventName') == 'ObjectCreated:Put']
print("records : ", records)
if records:
awsRegion = records[0].get('awsRegion', '')
info = records[0].get('s3', {})
file_key = info.get('object', {}).get('key')
bucket_name = info.get('bucket', {}).get('name')
message = {
'body' : "Script execution completed. See https://console.amazonaws.com/s3/buckets/" + bucket_name + "/" + file_key.replace('err', 'out') + "/?region=" + awsRegion + "&tab=overview for complete output"
}
print message
return message
早期事件具有参数('event is : ', {u'number': u'1'})
脚本执行后,事件保存s3键的名称-
{cd2}
目前没有回答
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