擅长:python、mysql、java
<p><strong><em>选项1</em></strong><br/>
<code>stack</code>然后<code>nlargest</code></p>
<pre><code>df.stack().nlargest(1)
Cat Zebra 3
dtype: int64
</code></pre>
<hr/>
<p><strong><em>选项2</em></strong><br/>
<code>stack</code>然后<code>idxmax</code></p>
^{pr2}$