我有一个正在工作的谷歌美国石油学会我所访问的项目,要求它打开一个组件,它将json发布到一个webhook URL,我的nodejs解析json,在raspberry上执行python脚本。问题是,很明显,仅仅调用欢迎意图就会触发json post并切换python脚本来打开组件。奇怪的是if语句决定调用哪个python脚本所需的组件状态在欢迎意向状态下为空。在
这是我的节点.js公司名称:
'use strict';
require('dotenv').config();
const PythonShell = require('python-shell');
const fs = require('fs');
const express = require('express');
const bodyParser= require('body-parser');
const path = require('path')
const app = express();
process.env.DEBUG = 'actions-on-google:*';
let Assistant = require('actions-on-google').ApiAiAssistant;
app.use(bodyParser.json({type: 'application/json'}));
const GENERATE_ANSWER_ACTION = 'generate_answer';
const EXECUTE_HOME_COMMAND = 'execute_home_command';
const switches = [];
var readableStream = fs.createReadStream('saveState.json');
var data = ''
readableStream.on('data', function(chunk) {
data+=chunk;
});
readableStream.on('end', function() {
var parsed = JSON.parse(data);
for (var i=0;i<parsed.switches.length;i++){
switches.push(new Switch(parsed.switches[i]))
}
});
function Switch(switchValues){
this.id = switchValues.id || "sw"
this.state = switchValues.state || "off"
this.name = switchValues.name || "switch"
this.toggle = function(){
if(this.state === "on"){
this.setState("off")
}
else{
this.setState("on");
}
}
this.setState = function(state){
var str = state === "on" ? onString(this.id[2]) : offString(this.id[2]);
PythonShell.run(str, function (err) {
if (!process.env.DEV){
if (err) throw err;
}
});
this.state = state
}
this.setState(this.state);
}
function onString(number){
return './public/python/sw' + number + '_on.py'
}
function offString(number){
return './public/python/sw' + number + '_off.py'
}
function getSwitch(string){
return switches.filter(function(element){
return element.id === string;
})[0]
}
function saveState (){
var formattedState = {
switches: switches
}
fs.writeFile('./saveState.json', JSON.stringify(formattedState) )
}
app.use(bodyParser.urlencoded({ extended: true }))
app.use(express.static(__dirname + '/public'));
app.get('/', function(req, res){
res.sendFile('index');
})
// Switch Routes for API
app.get('/api/switches', function(req, res){
res.send(switches);
})
app.get('/api/switches/:id', function(req, res){
var found = getSwitch(req.params.id);
res.json(found);
})
app.post('/api/switches/:id', function(req, res){
console.log('headers: ' + JSON.stringify(req.headers));
console.log('body: ' + JSON.stringify(req.body));
const assistant = new Assistant({request: req, response: res});
let soc = assistant.getArgument('state-of-component')
function generateAnswer(assistant) {
console.log('genera answer');
assistant.ask('I\'m thinking of a number from 0 and 100. What\'s your first guess?');
}
function executeHomeCommand(assistant) {
console.log('revisear guess');
console.log(soc);
if (soc === "on") {
console.log('SUCCESS soc=ON');
} else {
console.log('FAILUER soc=OFF');
}
}
// //MAP ACTIONS to functions
let actionMap = new Map();
actionMap.set(GENERATE_ANSWER_ACTION, generateAnswer);
actionMap.set(EXECUTE_HOME_COMMAND, executeHomeCommand);
assistant.handleRequest(actionMap);
if (req.query.password === process.env.PASS){
var foundSwitch = getSwitch(req.params.id);
if (soc === "on") {
foundSwitch.setState("on");
console.log('SWITCHING ON');
} else {
foundSwitch.setState("off");
console.log('SWITCHING OFF');
}
saveState();
console.log("postSwitch "+JSON.stringify(foundSwitch));
res.json(foundSwitch);
}
else {
console.log("invalid password")
res.send("try again")
}
})
app.listen(process.env.PORT, function(){
console.log('Listening on port ' + process.env.PORT);
})
我以为是我的应用程序js代码发布在欢迎意向上,但我不太确定,因为在欢迎意向上,组件的状态是空的,没有值,所以soc是!=“on”,所以if语句工作正常。问题是:
^{pr2}$代码也是出于欢迎的意图而被调用的,它不应该被调用。在
好吧,真正的问题是你似乎在处理所有的意图,而不是基于特定意图的特定事物。与美国石油学会,您有两种方法来处理此问题:
对于特定的目的,您始终可以关闭webhook解析,而对于其他目的,您仍然可以保持启用状态。在本例中,您可以出于欢迎目的(这将发送问候提示等)而将其关闭,但对于其他命令处理,则将其打开。
一旦你的webhook被调用,googlelibrary上的操作将决定调用它所调用的操作的特定函数。这是通过
assistant.handleRequest(actionMap);
行来处理的。在您的代码中,在调用
assistant.handleRequest(actionMap);
之后,会发生额外的处理。所以每次调用都会处理这个额外的代码。听起来这不是你想要的。在您应该将此代码移到向actionMap注册的特定操作处理代码中。(我不知道您的操作是什么,但我假设将代码放在executeHomeCommand()函数中最有意义,假设其他所有操作都正确连接。)
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