擅长:python、mysql、java
<p><code>bytes</code>构造函数接受一个整数的iterable,因此只需将您的列表馈送给它:</p>
<pre><code>l = list(range(0, 256, 23))
print(l)
b = bytes(l)
print(b)
</code></pre>
<p>输出:</p>
<pre><code>[0, 23, 46, 69, 92, 115, 138, 161, 184, 207, 230, 253]
b'\x00\x17.E\\s\x8a\xa1\xb8\xcf\xe6\xfd'
</code></pre>
<p>另请参见:<a href="https://stackoverflow.com/questions/18640175/python-3-on-converting-from-ints-to-bytes-and-then-concatenating-them-for-s?rq=1">Python 3 - on converting from ints to 'bytes' and then concatenating them (for serial transmission)</a></p>