Python与Ruby中的RSA加密

Question

我试图用Python和Ruby加密一个小字符串。我用这两种语言编写的代码应该完全相同：

在Python中：

from Crypto.PublicKey import RSA
from Crypto.Util import asn1
from Crypto import Random
import sys, time, signal, socket, requests, re, base64

pubkey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

foobar = "foobar"

pubkey_int = long(pubkey,16)
pub_exp = 65537L
pubkey_obj = RSA.construct((pubkey_int, pub_exp))
encypted_data =  pubkey_obj.encrypt(foobar, pub_exp)
encypted_data_b64 = base64.b64encode(encypted_data[0])

print encypted_data_b64

在Ruby中：

^{pr2}$

这两个脚本都试图使用相同的公钥加密字符串foobar。我希望它们每次都能输出相同的结果，但事实并非如此。此外，每次执行Ruby脚本时，它都会输出不同的结果。在

有人能帮我找出这两个脚本之间的区别吗？在

Answer 1

我可以通过阅读Class _RSAobj（https://www.dlitz.net/software/pycrypto/api/current/Crypto.PublicKey.RSA._RSAobj-class.html#encrypt）的文档来解决这个问题

Attention: this function performs the plain, primitive RSA encryption (textbook). In real applications, you always need to use proper cryptographic padding, and you should not directly encrypt data with this method. Failure to do so may lead to security vulnerabilities. It is recommended to use modules Crypto.Cipher.PKCS1_OAEP or Crypto.Cipher.PKCS1_v1_5 instead.

在RSA模块for Python中，默认情况下不会使用加密填充，因此存在差异。在

修改的Python脚本：

from Crypto.PublicKey import RSA
from Crypto.Cipher import PKCS1_v1_5
import sys, time, signal, socket, requests, re, base64

pubkey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

foobar = "foobar"

pubkey_int = long(pubkey,16)
pub_exp = 65537L
pubkey_obj = RSA.construct((pubkey_int, pub_exp))
cipher = PKCS1_v1_5.new(pubkey_obj)
encypted_data = cipher.encrypt(foobar)
encypted_data_b64 = base64.b64encode(encypted_data)

print encypted_data_b64