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<p>我有一个代表扑克牌的字符串列表。等级可以是</p>
<p>甲3456789TJQK</p>
<p>这是我的名单</p>
<pre><code># L2
['5', '6', '7', 'A', 'K']
</code></pre>
<p>我试图用排序函数中的键调用一个函数,以按顺序返回卡片等级的数值。我的职能是:</p>
^{pr2}$
<p>我的电话是:</p>
<pre><code>L4 = sorted(L2, key = sortYo())
</code></pre>
<p>但我的L4最终还是一样:</p>
<pre><code># L4
['5', '6', '7', 'A', 'K']
</code></pre>
<p>为什么我的sortYo()函数不更改值?提前谢谢你。在</p>
<p>编辑:</p>
<pre><code>from collections import Counter
from itertools import combinations
import sys
myList = sys.argv
myList.pop(0)
Suits = ['H', 'S', 'D', 'C']
Nums = ['A', '2', '3', '4', '5', '6', '7', '8', '9', 'T', 'J', 'Q', 'K']
SuitsTwo = {'♥': 'H', '♦': 'D', '♣': 'C', '♠': 'S'}
print(myList)
L1 = [] # Suits
L2 = [] # Ranks
L3 = [i for i in myList[0]] # Cut
for i in myList:
for x in i:
if x in SuitsTwo:
L1.append(SuitsTwo[x])
elif x in Suits:
L1.append(x)
else:
L2.append(x)
print('L1:'
print(L1)
print('L2:')
print(L2)
print('L3:')
print(L3)
score = 0
# straight
sC = 0
myDict = {'A': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9\
': 9, 'T': 10, 'J': 10, 'Q': 10, 'K': 10}
L4 = sorted(L2, key = lambda x: myDict.get(x,11))
print('L4')
print(L4)
#RUN
python3 as13.py AS 5H 6C 7S KH
['AS', '5H', '6C', '7S', 'KH']
L1:
['S', 'H', 'C', 'S', 'H']
L2:
['A', '5', '6', '7', 'K']
L3:
['A', 'S']
L4
['A', '5', '6', '7', 'K']
0
</code></pre>