使用匹配键组合行

2024-10-02 00:35:02 发布

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我有一个具有以下结构的文本文件

ID,operator,a,b,c,d,true
WCBP12236,J1,75.7,80.6,65.9,83.2,82.1
WCBP12236,J2,76.3,79.6,61.7,81.9,82.1
WCBP12236,S1,77.2,81.5,69.4,84.1,82.1
WCBP12236,S2,68.0,68.0,53.2,68.5,82.1
WCBP12234,J1,63.7,67.7,72.2,71.6,75.3
WCBP12234,J2,68.6,68.4,41.4,68.9,75.3
WCBP12234,S1,81.8,82.7,67.0,87.5,75.3
WCBP12234,S2,66.6,67.9,53.0,70.7,75.3
WCBP12238,J1,78.6,79.0,56.2,82.1,84.1
WCBP12239,J2,66.6,72.9,79.5,76.6,82.1
WCBP12239,S1,86.6,87.8,23.0,23.0,82.1
WCBP12239,S2,86.0,86.9,62.3,89.7,82.1
WCBP12239,J1,70.9,71.3,66.0,73.7,82.1
WCBP12238,J2,75.1,75.2,54.3,76.4,84.1
WCBP12238,S1,65.9,66.0,40.2,66.5,84.1
WCBP12238,S2,72.7,73.2,52.6,73.9,84.1

每个ID对应一个数据集，该数据集由一个运算符分析多次。i、 eJ1和J2是运算符J的第一次和第二次尝试。度量a、b、c和{}使用4种稍有不同的算法来测量一个值，该值的真值位于true列中

我想做的是创建3个新的文本文件，比较J1vsJ2，S1vsS2和{}vsS1的结果。J1vsJ2的示例输出：

^{pr2}$

其中a1是J1等的测量a

另一个例子是S1vsS2：

ID,operator,a1,a2,b1,b2,c1,c2,d1,d2,true
WCBP12236,77.2,68.0,81.5,68.0,69.4,53.2,84.1,68.5,82.1
WCBP12234,81.8,66.6,82.7,67.9,67.0,53,87.5,70.7,75.3

ID将不会按字母数字顺序排列，也不会为同一个ID聚集运算符。我不确定如何最好地处理此任务—使用linux工具或perl/python之类的脚本语言。在

我最初使用linux的尝试很快就遇到了困难

首先查找所有唯一ID（排序）

awk -F, '/^WCBP/ {print $1}' file | uniq | sort -k 1.5n > unique_ids

循环这些ID并排序J1，J2：

foreach i (`more unique_ids`)
    grep $i test.txt | egrep 'J[1-2]' | sort -t',' -k2
end

给我分类的数据

WCBP12234,J1,63.7,67.7,72.2,71.6,75.3
WCBP12234,J2,68.6,68.4,41.4,68.9,80.4
WCBP12236,J1,75.7,80.6,65.9,83.2,82.1
WCBP12236,J2,76.3,79.6,61.7,81.9,82.1
WCBP12238,J1,78.6,79.0,56.2,82.1,82.1
WCBP12238,J2,75.1,75.2,54.3,76.4,82.1
WCBP12239,J1,70.9,71.3,66.0,73.7,75.3
WCBP12239,J2,66.6,72.9,79.5,76.6,75.3

我不知道如何重新排列这些数据以获得所需的结构。我尝试在foreach循环awk 'BEGIN {RS="\n\n"} {print $1, $3,$10,$4,$11,$5,$12,$6,$13,$7}'中的awk添加一个额外的管道

有什么想法吗？我确信使用awk可以以一种不那么麻烦的方式完成，尽管使用适当的脚本语言可能会更好。在


Tags： 数据idtrue运算符结构文本文件s2awk
3条回答
网友
1楼 · 编辑于 2024-10-02 00:35:02

我没有像TLP那样使用Text:：CSV。如果你需要的话，你可以，但是在这个例子中，我想因为字段中没有嵌入逗号，所以我对'，'做了一个简单的拆分。另外，两个运算符的真字段都列出来了（而不是1），因为我认为最后一个值的特殊情况会使解决方案复杂化。在

#!/usr/bin/perl
use strict;
use warnings;
use List::MoreUtils qw/ mesh /;

my %data;

while (<DATA>) {
    chomp;
    my ($id, $op, @vals) = split /,/;
    $data{$id}{$op} = \@vals;
}

my @ops = ([qw/J1 J2/], [qw/S1 S2/], [qw/J1 S1/]);

for my $id (sort keys %data) {
    for my $comb (@ops) {
        open my $fh, ">>", "@$comb.txt" or die $!;
        my $a1 = $data{$id}{ $comb->[0] };
        my $a2 = $data{$id}{ $comb->[1] };
        print $fh join(",", $id, mesh(@$a1, @$a2)), "\n";
        close $fh or die $!;
    }   
}

__DATA__
WCBP12236,J1,75.7,80.6,65.9,83.2,82.1
WCBP12236,J2,76.3,79.6,61.7,81.9,82.1
WCBP12236,S1,77.2,81.5,69.4,84.1,82.1
WCBP12236,S2,68.0,68.0,53.2,68.5,82.1
WCBP12234,J1,63.7,67.7,72.2,71.6,75.3
WCBP12234,J2,68.6,68.4,41.4,68.9,75.3
WCBP12234,S1,81.8,82.7,67.0,87.5,75.3
WCBP12234,S2,66.6,67.9,53.0,70.7,75.3
WCBP12239,J1,78.6,79.0,56.2,82.1,82.1
WCBP12239,J2,66.6,72.9,79.5,76.6,82.1
WCBP12239,S1,86.6,87.8,23.0,23.0,82.1
WCBP12239,S2,86.0,86.9,62.3,89.7,82.1
WCBP12238,J1,70.9,71.3,66.0,73.7,84.1
WCBP12238,J2,75.1,75.2,54.3,76.4,84.1
WCBP12238,S1,65.9,66.0,40.2,66.5,84.1
WCBP12238,S2,72.7,73.2,52.6,73.9,84.1

产生的输出文件如下

J1 J2.txt

^{pr2}$

S1 S2.txt

WCBP12234,81.8,66.6,82.7,67.9,67.0,53.0,87.5,70.7,75.3,75.3
WCBP12236,77.2,68.0,81.5,68.0,69.4,53.2,84.1,68.5,82.1,82.1
WCBP12238,65.9,72.7,66.0,73.2,40.2,52.6,66.5,73.9,84.1,84.1
WCBP12239,86.6,86.0,87.8,86.9,23.0,62.3,23.0,89.7,82.1,82.1

J1 S1.txt

WCBP12234,63.7,81.8,67.7,82.7,72.2,67.0,71.6,87.5,75.3,75.3
WCBP12236,75.7,77.2,80.6,81.5,65.9,69.4,83.2,84.1,82.1,82.1
WCBP12238,70.9,65.9,71.3,66.0,66.0,40.2,73.7,66.5,84.1,84.1
WCBP12239,78.6,86.6,79.0,87.8,56.2,23.0,82.1,23.0,82.1,82.1

更新：为了只得到1个真值，for循环可以这样写：

for my $id (sort keys %data) {
    for my $comb (@ops) {
        local $" = '';
        open my $fh, ">>", "@$comb.txt" or die $!;
        my $a1 = $data{$id}{ $comb->[0] };
        my $a2 = $data{$id}{ $comb->[1] };
        pop @$a2;
        my @mesh = grep defined, mesh(@$a1, @$a2);
        print $fh join(",", $id, @mesh), "\n";
        close $fh or die $!;
    }   
}

更新：为grep expr中的测试添加了“defined”。因为这是正确的方法（而不是仅仅测试'$\'，它可能是0并且被grep错误地排除在列表之外）。在

网友
2楼 · 编辑于 2024-10-02 00:35:02

Python方式：

import os,sys, re, itertools
info=["WCBP12236,J1,75.7,80.6,65.9,83.2,82.1",
  "WCBP12236,J2,76.3,79.6,61.7,81.9,82.1",
  "WCBP12236,S1,77.2,81.5,69.4,84.1,82.1",
  "WCBP12236,S2,68.0,68.0,53.2,68.5,82.1",
  "WCBP12234,J1,63.7,67.7,72.2,71.6,75.3",
  "WCBP12234,J2,68.6,68.4,41.4,68.9,80.4",
  "WCBP12234,S1,81.8,82.7,67.0,87.5,75.3",
  "WCBP12234,S2,66.6,67.9,53.0,70.7,72.7",
  "WCBP12238,J1,78.6,79.0,56.2,82.1,82.1",
  "WCBP12239,J2,66.6,72.9,79.5,76.6,75.3",
  "WCBP12239,S1,86.6,87.8,23.0,23.0,82.1",
  "WCBP12239,S2,86.0,86.9,62.3,89.7,82.1",
  "WCBP12239,J1,70.9,71.3,66.0,73.7,75.3",
  "WCBP12238,J2,75.1,75.2,54.3,76.4,82.1",
  "WCBP12238,S1,65.9,66.0,40.2,66.5,80.4",
  "WCBP12238,S2,72.7,73.2,52.6,73.9,72.7" ]

def extract_data(operator_1, operator_2):
    operator_index=1
    id_index=0
    data={}
    result=[]
    ret=[]
    for line in info:
        conv_list=line.split(",")
        if len(conv_list) > operator_index and ((operator_1.strip().upper() == conv_list[operator_index].strip().upper()) or (operator_2.strip().upper() == conv_list[operator_index].strip().upper()) ):
            if data.has_key(conv_list[id_index]):
                iters = [iter(conv_list[int(operator_index)+1:]), iter(data[conv_list[id_index]])]
                data[conv_list[id_index]]=list(it.next() for it in itertools.cycle(iters))
                continue
            data[conv_list[id_index]]=conv_list[int(operator_index)+1:]
    return data

ret=extract_data("j1", "s2")
print ret

开/关：

{'WCBP12239': ['70.9', '86.0', '71.3', '86.9', '66.0', '62.3', '73.7', '89.7', '75.3', '82.1'], 'WCBP12238': ['72.7', '78.6', '73.2', '79.0', '52.6', '56.2', '73.9', '82.1', '72.7', '82.1'], 'WCBP12234': ['66.6', '63.7', '67.9', '67.7', '53.0', '72.2', '70.7', '71.6', '72.7', '75.3'], 'WCBP12236': ['68.0', '75.7', '68.0', '80.6', '53.2', '65.9', '68.5', '83.2', '82.1', '82.1']}

网友
3楼 · 编辑于 2024-10-02 00:35:02

您可以使用Perl csv模块Text::CSV提取字段，然后将它们存储在散列中，其中ID是主键，第二个字段是次关键字，所有字段都作为值存储。这样做任何你想做的比较都应该是微不足道的。如果要保留行的原始顺序，可以在第一个循环中使用数组。在

use strict;
use warnings;
use Text::CSV;

my %data;
my $csv = Text::CSV->new({
            binary => 1,      # safety precaution
            eol    => $/,     # important when using $csv->print()
    });
while ( my $row = $csv->getline(*ARGV) ) {
    my ($id, $J) = @$row;   # first two fields
    $data{$id}{$J} = $row;  # store line
}

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