PYTHON-反数猜测Gam

Question

所以我一直在想办法写一个程序，让电脑猜出我想的数字，而不是用另一种方法猜出电脑选择的数字。它在大多数情况下都是有效的，但是在某些情况下，它会在链上重复数字，即使我之前告诉过它，例如，我正在考虑的值高于“7”。在某些情况下，它还会重复相同的数字，即使我告诉它它的高或低。如果有更有经验的人可以看看这个，告诉我在这些循环中我遗漏了什么，这将有很大帮助。

#computer enters a value x
#lower - computer guesses lower than x
#higher - computer guesses higher than x
#when string "You got it!" - game over

import random

lowBound = 0
highBound = 100
randomNumber = random.randint(lowBound,highBound)

print ("Is it ", randomNumber, " ?")
response = input()

while response != "You got it!":
    if response == "higher":
        lowBound = randomNumber    
        randomNumber = random.randint (lowBound, highBound)
        print ("Is it ", randomNumber, " ?")
        response = input()

    elif response == "lower":
        highBound = randomNumber
        randomNumber = random.randint (lowBound, highBound)
        print ("Is it ", randomNumber, " ?")
        response = input()

    if response == "You got it!":

        print ("Woohooo, I'm so bitchin'")

Answer 1

在提到的其他问题中，你的一个问题是：

highBound = randomNumber
randomNumber = random.randint (lowBound, highBound)

你正在设置一个新的界限，这是好的，但然后你选择另一个随机数！

你应该做的，是将界限减半，然后从那里向用户询问高低。看看二进制搜索算法。

highBound = randomNumber
randomNumber = randomNumber / 2

你的程序仍然可以工作（这里提到的其他更改），但这会在大多数情况下更快地猜出你的号码。

实际上有an example of this game on Wikipedia.

Answer 2

random.randint是包含的，因此：

if response == 'higher':
    lowBound = randomNumber + 1

以及

if response == 'lower':
    highBound = randomNumber - 1

此外，如果用户没有输入有效的响应，将永远不会再次调用input()，程序将挂起在无限循环中。

更强大的东西，但不能对付骗子：

import random

lowBound = 0
highBound = 100
response = ''
randomNumber = random.randint(lowBound,highBound)

while response != "yes":
    print ("Is it ", randomNumber, " ?")
    response = input()
    if response == "higher":
        lowBound = randomNumber + 1   
        randomNumber = random.randint(lowBound,highBound)
    elif response == "lower":
        highBound = randomNumber - 1
        randomNumber = random.randint(lowBound,highBound)
    elif response == "yes":
        print ("Woohooo, I'm so bitchin'")
        break
    else:
        print ('Huh? "higher", "lower", or "yes" are valid responses.')

Answer 3

random.randint(a, b)返回一个介于a和b之间的数字。生成新的随机数时，应使用random.randint(lowBound+1, highBound-1)