当我运行当前代码时,我得到一个TypeError:'NoneType'对象不可读取。具体来说,main函数中的mostword=wordcount(wordlist)第62行,我在第19行的wordlist中添加了x。你能帮我找出哪里出了问题吗?在
def getwords():
#function to get words in the input file
try:
fp=open("sample.txt",'r')
except IOError:
print('Unable to open file')
return
words=[]
#read the file line by line
for line in fp:
#convert each line into words with space as delimiter
words=words+line.split()
return words
def wordcount(wordlist):
#function to count words in the file
#worddic is dictionary to store words frequency
worddic=dict()
for x in wordlist:
#convert word to lowercase to ignorecase
t=x.lower()
if(t not in worddic):
worddic[t]=0
worddic[t]=worddic[t]+1
max=-1
t=''
for x in worddic:
if(worddic[x]>max):
max=worddic[x]
t=x
return t
def letters(wordlist,lettercount):
#function to count letters in the file
for x in wordlist:
#For each word in the list
t=x.lower()
for y in t:
#for each letter in the word
if(not (y in lettercount)):
#if the letter is not in dictionary add it
#and set frequency to zero
lettercount[y]=0
#increment the frequency of letter in dictionary
lettercount[y] = lettercount[y]+1
def createoutput(lettercount,wordlist,mostword):
#creates an empty file 'statistics.txt'
try:
fout=open("statistics.txt",'w+')
except IOError:
print('Unable to create file')
fout.write('Number of words in the file are '+str(len(wordlist))+'\n')
fout.write('Most repeated word in the file is '+mostword+'\n')
for x in lettercount:
#write to the file 'statistics.txt'
fout.write(x+' appeared in the file for '+str(lettercount[x])+' times \n')
def main():
wordlist=getwords()
#lettercount is a dictionary with letters as keys
#and their frequency in the input file as data
lettercount=dict()
mostword=wordcount(wordlist)
letters(wordlist,lettercount)
createoutput(lettercount,wordlist,mostword)
main()
提前谢谢。非常感谢。在
您可以在函数
getwords
内的getwords
在try/except
块之后声明。如果IOException
被引发,您只需return
。这将在失败的open
上返回None
。将words = []
移到try/except
之前。在这段代码现在应该可以工作了,没有异常。在
我假设get words没有返回数组中的任何内容,因为您不正确地附加了行。在返回之前添加一个打印单词。当您调用get wordcount函数时,它以none类型不可编辑的方式进行答复。使用append函数代替
words = words.line.split()
。words.append(line.split())
相关问题 更多 >
编程相关推荐