擅长:python、mysql、java
<p>您的问题可以归结为展开嵌套列表并消除多余的条目:</p>
<pre><code>def flatten(nested, answer=None):
if answer is None:
answer = []
if nested == []:
return answer
else:
n = nested[0]
if is instance(n, tuple):
return flatten(nested[1:], nested(n[0], answer))
else:
return flatten(nested[1:], answer+n[0])
</code></pre>
<p>因此,使用嵌套字典:</p>
^{pr2}$
<p>如果要消除重复条目:</p>
^{3}$
<p>希望这有帮助</p>