擅长:python、mysql、java
<p>我想这应该能回答你的编辑:</p>
<pre><code>a = '111 = dw11qdwq\nsome other line\n111 = aaaaa'
b = re.split(r'(111 = )\S*', a)
d = ['qqqqqq','wwwwwww']
a = "".join(x + d.pop(0) if x == '111 = ' else x for x in b)
print a
</code></pre>
<p><strong>编辑</strong>:现在应该可以正确处理不匹配的文本。在</p>