我现在正在上python的一门课程,并在Codegrinder中做了一些让我感到悲伤的练习。我有以下课程:
MAX_LEAD_LENGTH = 10
MAX_NUM_LEADS = 5
class Pencil:
def __init__(self, num_leads):
self.mNumLeads = 0
self.mCurrentLeadLength = MAX_LEAD_LENGTH
self.addLeads(num_leads)
return
def getNumLeads(self):
return self.mNumLeads
def getCurrentLeadLength(self):
return self.mCurrentLeadLength
def click(self):
if self.mCurrentLeadLength > 0:
self.mCurrentLeadLength -= 1
if self.mCurrentLeadLength == 0 and self.mNumLeads > 0:
self.mCurrentLeadLength = MAX_LEAD_LENGTH
self.mNumLeads -= 1
return self.mCurrentLeadLength > 0
def addLeads(self, num_additional_leads):
if num_additional_leads > 0:
self.mNumLeads += num_additional_leads
if self.mNumLeads > MAX_NUM_LEADS:
self.mNumLeads = MAX_NUM_LEADS
return self.mNumLeads
说明如下:
Exercise: query01
Description
In this exercise, you will create a function that receives a Pencil object as a parameter. It will return the length of the current lead in the pencil.
Function Name
query01
Parameters
- pencil: A Pencil object
Return Value
- The length of the current lead in pencil.
Examples
p = Pencil(3) p.click() query01(p) -> a number representing the length
如何编写此函数以接收作为函数参数的对象?在
你的任务是返回一个方法。而是返回当前长度。您已经将此函数设为
getCurrentLeadLength
。在对象已经作为
self
参数进入方法中。在现在,对于给定的接口,您可能需要更改几个名称,但这实际上是伪装的
getCurrentLeadLength
。在相关问题 更多 >
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