Python如何验证tkinter输入字段

Question

在我的程序中，我有一个sqlite数据库，其中的数据通过tkintergui中的条目小部件附加到其中。我希望数据只在经过验证后才附加到数据库中，因为目前还没有验证。在

例如，在我的函数下面，它将customerID、forename、姓氏、地址和电话号码追加到数据库中的customer表中。我希望这样customerID条目只接受整数，名字、姓氏和地址不为空，phoneNumberEntry也只接受整数。在

我见过有人使用validatecommand，但我不认为我能够实现它，因为我已经在使用一个命令将数据追加到数据库中。在

def appendToCustomerTableEntry(event):
    top = Toplevel()
    top.title("Add to customer table")

    Label(top, text = "customerID: ").grid(sticky = E)

    customerIDEntry = Entry(top)
    customerIDEntry.grid(row = 0, column = 1)

    Label(top, text = "Forename: ").grid(row = 1, sticky = E)

    customerForenameEntry = Entry(top)
    customerForenameEntry.grid(row = 1, column = 1)

    Label(top, text = "Surname: ").grid(row = 2, sticky = E)

    customerSurnameEntry = Entry(top)
    customerSurnameEntry.grid(row = 2, column = 1)

    Label(top, text = "Address: ").grid(row = 3, sticky = E)

    customerAddressEntry = Entry(top)
    customerAddressEntry.grid(row = 3, column = 1)

    Label(top, text = "Phone Number: ").grid(row = 4, sticky = E)

    customerPhoneNumberEntry = Entry(top)
    customerPhoneNumberEntry.grid(row = 4, column = 1)

    exitButton = Button(top, text = "Exit", command = top.destroy)
    exitButton.grid(row = 5, column = 2, sticky = W)

    appendButton = Button(top, text = "Append", command =   lambda:appendToCustomerTable
                  (customerIDEntry.get(), customerForenameEntry.get(), customerSurnameEntry.get(),
                   customerAddressEntry.get(), customerPhoneNumberEntry.get()))
    appendButton.grid(row = 5, column = 1, sticky = E)


def appendToCustomerTable(customerID, Forename, Surname, Address, TelephoneNumber):
    c.execute("INSERT INTO customerTable VALUES (?, ?, ?, ?, ?);", (customerID, Forename, Surname, Address, TelephoneNumber ))
    conn.commit()

Answer 1

这是sql卫生问题，还是python编程问题？在

如果sql环境卫生，您需要确定要拒绝哪些sql字符串或字符，也可能有库可以做到这一点。 https://www.owasp.org/index.php/SQL_Injection_Prevention_Cheat_Sheet

在程序上，可以运行if语句，改变操作顺序并使用字符串替换。 http://bobby-tables.com/python.html

在你的代码中，你要注意的似乎是有人试图通过你的字段发布代码。看看最后一个链接。在

Answer 2

首先尝试“dont repeat your self”

# you can declare here the input type of your argument default and the type of them 
def build(ui_title = [], int_arg = 0):
    # on top you can also assert the input
    # continue only if ui_title is True else give a AssertionError 
    assert (ui_title), "list is empty!!!"

    # lets check int_arg for int
    assert (int_arg==int), "{0} except int get {1}".format(int_arg ,type(int_arg))

    for row,text in enumerate(ui_title):
        Label(top, text = str(text)).grid(sticky = E)
        customerIDEntry = Entry(top)
        customerIDEntry.grid(row = int(row), column = 1)
        if text=="Exit":
            exitButton = Button(top, text = str(text), command = top.destroy)
            exitButton.grid(row = int(row), column = 2, sticky = W)

ui_title = ["customerID", "Forename: ", "Surname: ", "Address: ", "Phone Number: ", "Exit"]
build(ui_title) # will work
build(ui_title, int_arg = "Hallo") # will not work, because int_arg get string and the build method will raise a AssertionError