如何检查在pytestq中单击按钮后正确打开窗口

Question

我想在我的项目中测试一个模块，但是我有一些问题。我不知道怎样才能在按下按钮后检查窗口是否正确打开。在

我让窗口选择AddingBookTypeWindow和AddSchoolBookWindow。 我想检查一下AddSchoolBookWindow在我点击selectBtn按钮后是否会打开。在

我当前的测试（我对最后一个字符串有问题，因为我不知道必须使用哪种方法）：

@pytest.fixture
def open_window(qtbot):
    def _press_button(window):
        widget = window()
        qtbot.addWidget(widget)
        widget.show()
        qtbot.wait_for_window_shown(widget)
        sleep(3)
        return widget
    return _press_button


class TestSelectAddingBookTypeWindow:
    def test_select_schoolbook(self, open_window, qtbot):
        widget = open_window(SelectAddingBookTypeWindow)
        qtbot.mouseClick(widget.schoolbookSelector, QtCore.Qt.LeftButton)
        qtbot.mouseClick(widget.selectBtn, QtCore.Qt.LeftButton)
        assert widget.close()
        assert AddSchoolBookWindow.isActiveWindow()

我的课程： A、 选择AddingBookTypeWindow

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B.添加教科书窗口

class AddSchoolBookWindow(QDialog, Ui_AddSchoolbookWindow):
    @logger.catch
    def __init__(self):
        super().__init__()
        self.setupUi(self)
        self.widgets = [
            self.schoolbookAuthor, self.schoolbookTitle, self.schoolbookPublishHouse,
            self.schoolbookPublishYear, self.schoolbookInvoiceNum, self.schoolbookInvoiceDate, self.schoolbookClass,
            self.schoolbookCount, self.schoolbookPrice
        ]
        self.schoolbookSaveBtn.clicked.connect(lambda _: self.save_book())
        self.schoolbookClearBtn.clicked.connect(lambda _: Utils.clear_fields(self.widgets, self.schoolbookInvoiceDate))
        self.schoolbookCancelBtn.clicked.connect(lambda _: self.close())

    @logger.catch
    def save_book(self):
        field_names = Config.COLUMNS['SchoolBook']
        user_data = list(map(lambda x: x.text(), self.widgets))
        book_sum = Utils.calculate_book_sum(user_data)
        user_data.append(str(book_sum))
        book = dict(zip(field_names[1:], user_data))
        db = DatabaseManager(Config.PATHES['TO_DATABASE']['PROD'])
        model = Schoolbook('SchoolBook', db.connection)
        model.insert_book(book)
        logger.success(f'The {book} success add in the database')
        model.model.select()

这只是完整代码的一小部分，但是完整代码不能解决这个问题。在

Answer 1

在您的例子中，问题是小部件不可访问，因为它是一个局部变量，我也怀疑窗口是否会显示为稍后应该删除的窗口，因此要访问它，我将创建一个属性：

class SelectBookTypeWindow(QtWidgets.QDialog, Ui_selectBookTypeWindow):
    def __init__(self, widget1, widget2):
        super().__init__()
        self.setupUi(self)
        self.selectBtn.clicked.connect(lambda x: self.open_new_window(widget1, widget2))

        self._selected_window = None

    @property
    def selected_window(self):
        return self._selected_window

    def open_new_window(self, schoolbook_widget, fictionbook_widget):
        if self.schoolbookSelector.isChecked():
            self._selected_window = schoolbook_widget()
        elif self.fictionbookSelector.isChecked():
            self._selected_window = fictionbook_widget()
        if self.selected_window is not None:
            self.selected_window.show()
            self.close()

然后在测试中，你应该验证所选的窗口不是None，它的基类是AddSchoolBookWindow，也要避免使用时间。睡觉（），在测试的情况下使用QTest.qWait()

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