如何分解元组，以便将其作为参数列表传递？

Question

假设我有这样一个方法定义：

def myMethod(a, b, c, d, e)

然后，我有一个变量和一个像这样的元组：

myVariable = 1
myTuple = (2, 3, 4, 5)

有没有方法可以传递explode元组以便将其成员作为参数传递？类似这样的东西（尽管我知道这不起作用，因为整个元组被认为是第二个参数）：

myMethod(myVariable, myTuple)

如果可能的话，我想避免单独引用每个元组成员。。。

Answer 1

您正在查找argument unpacking运算符*：

myMethod(myVariable, *myTuple)

Answer 2

从Python documentation：

The reverse situation occurs when the arguments are already in a list or tuple but need to be unpacked for a function call requiring separate positional arguments. For instance, the built-in range() function expects separate start and stop arguments. If they are not available separately, write the function call with the *-operator to unpack the arguments out of a list or tuple:

>>> range(3, 6)             # normal call with separate arguments
[3, 4, 5]
>>> args = [3, 6]
>>> range(*args)            # call with arguments unpacked from a list
[3, 4, 5]

In the same fashion, dictionaries can deliver keyword arguments with the **-operator:

>>> def parrot(voltage, state='a stiff', action='voom'):
...     print "-- This parrot wouldn't", action,
...     print "if you put", voltage, "volts through it.",
...     print "E's", state, "!"
...
>>> d = {"voltage": "four million", "state": "bleedin' demised", "action": "VOOM"}
>>> parrot(**d)
-- This parrot wouldn't VOOM if you put four million volts through it. E's bleedin' demised !