在使用python将值写入csv文件之前，将其与字段名进行比较

Question

我用这段代码将值与它们关联的字段名进行比较，然后再将其存储在csv文件中以检查正确的列，因为每次重新启动计算机时，字典中传感器的顺序都会自动更改。这就是为什么在我将值存储到csv文件之前，我必须控制dict中的值的位置，否则我将得到一个混乱的csv文件，如下面的示例，它提供的值温度是1000[°C]亮度10[lux]

import csv
from datetime import datetime
import os
import time
from collections import OrderedDict
from time import sleep


Datum = time.strftime("%Y-%m-%d")
Time = datetime.now().replace(microsecond=0).isoformat()

data = {'Stecker Energy': '2.37', 'Stromzaehler Strom L1 [A]': '0.0', '1OG Ultraviolet': '0.0','Stecker EG  Energie [kWh]': '4.3'}

filename = Datum + 'SOF.csv'
if not os.path.isfile(filename):
    outfile = open(filename, "w")
    lineKey = ""
    for x in data.keys():
        lineKey+= x + ","
    lineKey = 'Time '+ "," + lineKey[:-1]+"\n" # Delete last character and add new line
    outfile = open(filename, "a")
    outfile.write(lineKey)
    outfile.close()

#check first line of  fieldnames 
with open(filename,'r') as myFile:
    reader = csv.DictReader(myFile)
    fieldnames = reader.fieldnames
    myFile.close()
#Compare the values with their  keys (fieldnames)
with open(filename,'a') as outfile:
    lineValue = ""
    for sensor, value  in data.items():
        if sensor in data.items()==sensor in fieldnames:
            v = data[sensor]
            print("v", v)
            lineValue+= str(v) + "," 
    lineValue = Time + "," + lineValue[:-1] + "\n"
    print(lineValue)
    outfile.write(lineValue)
    outfile.close()

问题是当我检查CSV文件时，我发现值写在错误的列中，这意味着错误的字段名，例如：

此问题在CSV文件中的示例

CSV文本示例

时间，Stromzaehler Strom L1[A]，Stecker Energy，1OG紫外线，Stecker EG Energie[kWh] 2017-11-21T17:56:10,2.37,0.0,0.0,4.3 2017-11-21T17:56:26,4.3,0.0,0.0,2.37 2017-11-21T17:56:28,0,0.0,2.37,4.3 2017-11-21T17:56:30,0,2.37,0.0,4.3

^{pr2}$

Answer 1

for sensor, value  in data.items():
    if sensor in data.items()==sensor in fieldnames:
        v = data[sensor]
        print("v", v)
        lineValue+= str(v) + "," 

我觉得这不对劲。如果您只想遍历所有字段名（而不是“Time”）并在data中添加与这些字段对应的值，同时为data中不存在的值加上“n/a”，那么我建议您：

^{pr2}$

---

额外建议：手动在值之间添加逗号是一种容易出错的方法。如果可能，请使用DictWriter，它可以为您解决大多数格式问题。在

with open(filename,'a') as outfile:
    writer = csv.DictWriter(outfile, fieldnames)
    row = {}    
    for fieldname in fieldnames: #no need to skip Time here, we'll just overwrite it later.
        row[fieldname] = data.get(fieldname, "n/a")
    row["Time "] = Time
    writer.writerow(row)

如果您坚持不这样做，至少将这些值存储在一个列表中，最后join一次：

with open(filename,'a') as outfile:
    values = [Time]
    for fieldname in fieldnames[1:]:
        v = data.get(fieldname, "n/a")
        values.append(str(v))
    outfile.write(",".join(values) + "\n")

---

额外的建议：如果这些解决方案在您不想要的行之间添加了额外的空行，您可以使用newline=""参数打开文件（如果使用python3）：

with open(filename,'a', newline="") as outfile:

。。。或者以二进制模式打开文件（如果使用Python 2）：

with open(filename,'ab') as outfile: