字典键和deque，不要工作第二个popleft或第一个pop。python

Question

我是python中的一个乞丐，我有一个字典，它的键名和值都是deque，当我添加deque时，它是有效的，但是当我试图用poplieft退出时，只有第一个有效

from collections import deque

class EmployeePoint:

    dic = {}

    def __init__(self,name,point):

        self.name = name
        self.point = point


people1 = EmployeePoint("Rafael","18")
people2 = EmployeePoint("Rafael","19")
people3 = EmployeePoint("Rafael","20")

EmployeePoint.dic["Rafael"] = deque([people1])
EmployeePoint.dic["Rafael"].append([people2])
EmployeePoint.dic["Rafael"].append([people3])


print EmployeePoint.dic["Rafael"].popleft().point
print EmployeePoint.dic["Rafael"].popleft().point

回溯：

十八 回溯（最近一次呼叫）： “文件”主.py“，第23行，英寸 打印雇员点.dic[“Rafael”].popleft（）.point AttributeError:“list”对象没有属性“point”

Answer 1

使用deque([people1])初始化deque可以，但不应该在列表中附加一个项目（即[people2]，而应该是.append(people2)

from collections import deque

class EmployeePoint:

    dic = {}

    def __init__(self,name,point):

        self.name = name
        self.point = point


people1 = EmployeePoint("Rafael","18")
people2 = EmployeePoint("Rafael","19")
people3 = EmployeePoint("Rafael","20")

EmployeePoint.dic["Rafael"] = deque([people1])
EmployeePoint.dic["Rafael"].append(people2)
EmployeePoint.dic["Rafael"].append(people3)


print (EmployeePoint.dic["Rafael"].popleft().point)
print (EmployeePoint.dic["Rafael"].popleft().point) 
# py3 print paretheses 

输出：

18

19