用Python正则表达式分析文本重新查找

Question

我有一个很长的字符串，需要分组解析，但需要更多地控制它。在

import re

RAW_Data = "Name Multiple Words Testing With 1234 Numbers and this stuff* ((Bla Bla Bla (Bla Bla) A40 & A41)) Name Multiple Words Testing With 3456 Numbers and this stuff2* ((Bla Bla Bla (Bla Bla) A42 & A43)) Name Multiple Words Testing With 78910 Numbers and this stuff3* ((Bla Bla Bla (Bla Bla) A44 & A45)) Name Multiple Words Testing With 1234 Numbers and this stuff4* ((Bla Bla Bla (Bla Bla) A46 & A47)) Name Multiple Words Testing With 1234 Numbers and this stuff5* ((Bla Bla Bla (Bla Bla) A48 & A49)) Name Multiple Words Testing With 1234 Numbers and this stuff6* ((Bla Bla Bla (Bla Bla) A50 & A51)) Name Multiple Words Testing With 1234 Numbers and this stuff7* ((Bla Bla Bla (Bla Bla) A52 & A53)) Name Multiple Words Testing With 1234 Numbers and this stuff8* ((Bla Bla Bla (Bla Bla) A54 & A55)) Name Multiple Words Testing With 1234 Numbers and this stuff9* ((Bla Bla Bla (Bla Bla) A56 & A57)) Name Multiple Words Testing With 1234 Numbers and this stuff10* ((Bla Bla Bla (Bla Bla) A58 & A59)) Name Multiple Words Testing With 1234 Numbers and this stuff11* ((Bla Bla Bla (Bla Bla) A60 & A61)) Name Multiple Words Testing With 1234 Numbers and this stuff12* ((Bla Bla Bla (Bla Bla) A62 & A63)) Name Multiple Words Testing With 1234 Numbers and this stuff13* ((Bla Bla Bla (Bla Bla) A64 & A65)) Name Multiple Words Testing With 1234 Numbers and this stuff14* ((Bla Bla Bla (Bla Bla) A66 & A67)) Name Multiple Words Testing With 1234 Numbers and this stuff15* ((Bla Bla Bla (Bla Bla) A68 & A69)) Name Multiple Words Testing With 1234 Numbers and this stuff16*"

fromnode = re.findall('(.*?)(?=\*\s)', RAW_Data)

print fromnode

del fromnode
del RAW_Data

结果是：“用1234个数字和这个东西命名多个单词测试”、“，”（（Bla-Bla（Bla-Bla）A40&A41））用3456个数字和这个stuff2'命名多个单词测试。。。。。。。。等等。

我似乎不能只捕获诸如“用3456个数字命名多个单词测试”之类的字符串，而忽略诸如“（（Bla-Bla（Bla-Bla）A40&A41））”之类的字符串。任何帮助都将不胜感激。在

Answer 1

你可以用

r'\*\s*\({2}.*?\){2}\s*'

模式（see demo）匹配：

• \*-一个文本星号
• \s*-零个或多个空白
• \({2}-正好2个左括号
• .*?-除换行符之外的零个或多个字符（注意：如果需要跨多行匹配，请添加re.S标志），直到第一个字符为止
• \){2}-双右括号
• \s*-0+空格。在

另外：same, but unrolled (thus, a bit more efficient) regex：

^{pr2}$

见IDEONE demo：

import re
p = re.compile(r'\*\s*\({2}.*?\){2}\s*')
test_str = "Name Multiple Words Testing With 1234 Numbers and this stuff* ((Bla Bla Bla (Bla Bla) A40 & A41)) Name Multiple Words Testing With 3456 Numbers and this stuff2* ((Bla Bla Bla (Bla Bla) A42 & A43)) Name Multiple Words Testing With 78910 Numbers and this stuff3* ((Bla Bla Bla (Bla Bla) A44 & A45)) Name Multiple Words Testing With 1234 Numbers and this stuff4* ((Bla Bla Bla (Bla Bla) A46 & A47)) Name Multiple Words Testing With 1234 Numbers and this stuff5* ((Bla Bla Bla (Bla Bla) A48 & A49)) Name Multiple Words Testing With 1234 Numbers and this stuff6* ((Bla Bla Bla (Bla Bla) A50 & A51)) Name Multiple Words Testing With 1234 Numbers and this stuff7* ((Bla Bla Bla (Bla Bla) A52 & A53)) Name Multiple Words Testing With 1234 Numbers and this stuff8* ((Bla Bla Bla (Bla Bla) A54 & A55)) Name Multiple Words Testing With 1234 Numbers and this stuff9* ((Bla Bla Bla (Bla Bla) A56 & A57)) Name Multiple Words Testing With 1234 Numbers and this stuff10* ((Bla Bla Bla (Bla Bla) A58 & A59)) Name Multiple Words Testing With 1234 Numbers and this stuff11* ((Bla Bla Bla (Bla Bla) A60 & A61)) Name Multiple Words Testing With 1234 Numbers and this stuff12* ((Bla Bla Bla (Bla Bla) A62 & A63)) Name Multiple Words Testing With 1234 Numbers and this stuff13* ((Bla Bla Bla (Bla Bla) A64 & A65)) Name Multiple Words Testing With 1234 Numbers and this stuff14* ((Bla Bla Bla (Bla Bla) A66 & A67)) Name Multiple Words Testing With 1234 Numbers and this stuff15* ((Bla Bla Bla (Bla Bla) A68 & A69)) Name Multiple Words Testing With 1234 Numbers and this stuff16*"
print(re.split(p, test_str))

更新

用于re.findall的正则表达式：

(?:\*\s*\(\([^)]*(?:\)(?!\))[^)]*)*\)\))?\s*([^*]*(?:\*(?!\s*\(\()[^*]*)*)\s*

参见regex demo

它的样子吓坏了吗？它只是更简单的^{}的展开版本。在

参见IDEONE demo。在