python中自制随机数生成器的问题。（使用时间。时间())

Question

我很清楚python有一个内置的随机库，所以请不要在本文中引用它。我正在使用time.time()自己动手的方法。我做了一个简单的随机数生成器，如下所示：

def random(x, y):
    import time
    choices = [i for i in range(x, y)]
    t = time.time()
    num = int(str(t-int(t))[2:])%100
    xnum = [i for i in range(num, choices[-1])]
    ynum = [choices[i] for i in xnum]
    znum = ynum[choices[num-1]]
    ret = choices[znum]
    return ret

这对于random(1, 200)之类的任何东西都很有效；但是，它也有一些问题。例如，如果我要做random(10, 200)，它将给出一个索引错误。我该如何改进/更改它，使它能够处理任意两个数字？在

Answer 1

这使用的逻辑与您的几乎完全相同，但不会超出范围。我明白这只是为了学习，但我觉得有必要说我不会用这个来代替random。无论如何，此代码不会崩溃：

from time import time
def randomNum(x, y):
    #ensures the function is called properly, you can handle this however you'd like to
    assert y > x and x > 0 

    choices = [i for i in range(x, y + 1)]
    t = time()

    #ensures that the number is less than y
    num = int(str(t-int(t))[2:])%y 
    xnum = [i for i in range(num, y)]

    #ensures that you don't get out of bounds for choices
    ynum = [choices[i%(y+1-x)] for i in xnum] 

    #same as above + ensure you don't go out of bounds for ynum, too
    znum = ynum[choices[(num-1)%(y-x)]%(y-num)]

    ret = choices[znum%(y+1-x)]
    return ret

NB：
虽然这不会崩溃，但它不会给出伪随机数，也就是说，如果你输入randomNum(1,10)，你将无法生成2、3或5。在