我正在尝试创建一个json文件,它可以将所有类别的项目从树结构中分解出来,并保持类别的嵌套顺序(来自这个网站http://www.isoldwhat.com/getcats/fullcategorytree.php)。目前,我有以下代码来解析所有类别:
#!/usr/bin/env python
import sys
import urllib2
from pprint import pprint
from bs4 import BeautifulSoup
def dataList(element):
categoryList = []
try:
for ul in categorySoup('ul', recursive=True):
for li in ul('li', recursive=True):
categoryList.append(li.a.contents)
categoryList.append("new ccategory");
return categoryList
except:
return ['broken!']
categories = ['20081', '550', '2984', '267', '12576', '625', '15032', '11450', '11116', '1', '58058', '293', '14339', '237', '11232', '45100', '99', '172008', '26395', '11700', '281', '11233', '619', '1281', '870', '10542', '316', '888', '64482', '260', '1305', '220', '3252', '1249']
print "\nSetting user agent...",
user_agent = 'Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10_6_4; en-US) AppleWebKit/534.3 (KHTML, like Gecko) Chrome/6.0.472.63 Safari/534.3'
print "DONE"
print "Setting headers...",
headers = { 'User-Agent' : user_agent }
print "DONE"
data = {}
print "Iterating through dictionary of categories\n"
for rootID in categories:
print "Requesting source code...",
url = 'http://www.isoldwhat.com/getcats/fullcategorytree.php?RootID=%s' % rootID
req = urllib2.Request(url, None, headers)
response = urllib2.urlopen(req)
print "DONE"
print "Turning HTML into soup..."
text = response.read()
soup = BeautifulSoup(text, 'html.parser')
categorySoup = soup.find('div', id='catnumbers')
print "DONE"
print "Parsing data...",
pprint(dataList(categorySoup))
print "DONE\n"
response.close() # its always safe to close an open connection
sys.exit()
print "Turning data into JSON...",
#data = find_li(soup)
data = json.dumps(data, ensure_ascii=False)
print "DONE\n"
print "Finished doing. Enjoy!"
这段代码的问题是它没有维护我需要的嵌套树结构。如何在保持嵌套类别的同时解析出类别?在
例如,可以使用
soup = BeautifulSoup("<b></b>")
创建一个新的根。并且只递归地追加类别和标记,同时保持相同的结构。关于以下内容:希望这能解决问题:)
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