为什么我不能用Python解析这个HTML页面？

Question

我试图用Python中的BeautifulSoup解析网页http://www.baseball-reference.com/teams/BOS/2000-pitching.shtml中的信息。我想在“团队投球”表格中打印出每个球员的相应姓名。但是，代码在某个特定的名字后面重复了球员的名字（在本例中，在第15行之后，它重复了“Pedro Martinez”）的名字。例如：

1 Pedro Martinez
2 Jeff Fassero*
3 Ramon Martinez
4 Pete Schourek*
5 Rolando Arrojo
6 Tomo Ohka
7 Derek Lowe
8 Tim Wakefield
9 Rich Garces
10 Rheal Cormier*
11 Hipolito Pichardo
12 Brian Rose
13 Bryce Florie
14 John Wasdin
15 Pedro Martinez
16 Jeff Fassero*
17 Ramon Martinez
18 Pete Schourek*
19 Rolando Arrojo
20 Tomo Ohka
21 Derek Lowe
22 Tim Wakefield
23 Rich Garces
24 Rheal Cormier*
25 Hipolito Pichardo
26 Brian Rose
27 Bryce Florie
28 John Wasdin

你知道发生了什么事吗？这是我的代码：

^{pr2}$

Answer 1

您试图遍历表中的所有行，而不是先获取所有表标记。因此，如果有意义的话，可以获取所有的table标记，然后遍历table标记中的所有tr标记。而且year和{}是未定义的，所以我假设年份是y，并使table变量{}。另外，您不必下载HTML，然后打开它来解析它，您只需通过获取连接的文本并直接解析来获得HTML。在

import urllib2
from bs4 import BeautifulSoup

# Download webpages 2010 webpage

y = 2010
url = 'http://www.baseball-reference.com/teams/BOS/'+ str(y) +'-pitching.shtml'
print 'Download from :', url

#dowlnload
filehandle = urllib2.urlopen(url)


fileout = 'YEARS'+str(y)+'.html'
print 'Save to : ', fileout, '\n'

#save file to disk
f = open(fileout,'w')
f.write(filehandle.read())
f.close()


# Read and parse the html file

# Parse information about the age of players in 2000

y = 2010

filein = 'YEARS' + str(y) + '.html'
print(filein)
soup = BeautifulSoup(open(filein))


table = soup.find_all('table', attrs={'id': 'team_pitching'}) #' non_qual' ''


for t in table:

    i = 1
    entries = t.find_all('tr', attrs={'class' : ''}) #' non_qual' ''
    print(len(entries))
    for entry in entries:
        columns = entry.find_all('td')
        printString = str(i) + ' '
        for col in columns:
            try:
                if ((',' in col['csk']) and (col['csk'] != '')):
                    printString = printString + col.text
                    i = i + 1
                    print printString
            except:
                pass