<pre><code>#Function takes a character and a string and returns a boolean reflecting if
#the character is found in the string.
def isItThereS(letter, word):
letInWord = 0
for l in word:
if l == letter:
letInWord += 1
return letInWord == True
</code></pre>
<p>当我把它放在接线员的时候</p>
<blockquote>
<blockquote>
<blockquote>
<p>isItThereS("h","hello world")
True</p>
</blockquote>
</blockquote>
</blockquote>
<p>但当我找到一个重复“l”或“o”的字符时,它返回false。在</p>
<blockquote>
<blockquote>
<blockquote>
<p>isItThereS("l","hello world")
False</p>
</blockquote>
</blockquote>
</blockquote>
<p>我该如何让它不返回false,而是返回True,因为字符在字符串中?在</p>