擅长:python、mysql、java
<p>如果nan=np.nan公司然后:</p>
<pre><code>import numpy as np
import math
NotPresent = ["Alan", "Susie", np.nan, np.nan, np.nan]
print(NotPresent)
n = len(NotPresent)
j = -1
for i in range(n):
j += 1
if not isinstance(NotPresent[j], str) and math.isnan(NotPresent[j]):
del NotPresent[j]
j = j-1
print(NotPresent)
</code></pre>
<p>输出将是:</p>
<p><code>['Alan', 'Susie', nan, nan, nan]</code></p>
<p><code>['Alan', 'Susie']</code></p>
<p>如果“nan”是字符串,则:</p>
^{pr2}$
<p>输出将是:</p>
<p><code>['Alan', 'Susie', "nan", "nan", "nan"]</code></p>
<p><code>['Alan', 'Susie']</code></p>