我有一个脚本,它工作得很好,直到我添加了一个文件查询框,用于用户交互。它不断重复这个问题,只有在以下命令出现时才会退出(shutil.copy2号文件)通过使输入/输出文件相同而被迫崩溃。为什么?在
import os, xml, arcpy, shutil, datetime, Tkinter,tkFileDialog
from xml.etree import ElementTree as et
path=os.getcwd()
RootDirectory=path
arcpy.env.workspace = path
Count=0
Generated_XMLs=RootDirectory+'\GeneratedXML_LOG.txt'
f = open(Generated_XMLs, 'a')
f.write("Log of Metadata Creation Process - Update: "+str(datetime.datetime.now())+"\n")
f.close()
for root, dirs, files in os.walk(RootDirectory, topdown=False):
#print root, dirs
for directory in dirs:
currentPath=os.path.join(root,directory)
os.chdir(currentPath)
arcpy.env.workspace = currentPath
print currentPath
#def Create_xml(currentPath):
FileList = arcpy.ListFeatureClasses()
zone="_Zone"
for File in FileList:
Count+=1
FileDesc_obj = arcpy.Describe(File)
FileNm=FileDesc_obj.file
print FileNm
check_meta=os.listdir(currentPath)
existingXML=FileNm[:FileNm.find('.')]
existingExtension=FileNm[FileNm.find('.'):]
print "XML: "+existingXML
print check_meta
#if existingXML+'.xml' in check_meta:
for f in check_meta:
if f.startswith(existingXML) and f.endswith('.xml'):
print "exists, file name:", f
newMetaFile=FileNm+"_2012Metadata.xml"
shutil.copy2(f, newMetaFile)
导致循环的代码
^{pr2}$其余工作代码
for node in tree.findall('.//title'):
node.text = str(FileNm)
for node in tree.findall('.//northbc'):
node.text = str(FileDesc_obj.extent.YMax)
for node in tree.findall('.//southbc'):
node.text = str(FileDesc_obj.extent.YMin)
for node in tree.findall('.//westbc'):
node.text = str(FileDesc_obj.extent.XMin)
for node in tree.findall('.//eastbc'):
node.text = str(FileDesc_obj.extent.XMax)
for node in tree.findall('.//native/nondig/formname'):
node.text = str(os.getcwd()+"\\"+File)
for node in tree.findall('.//native/digform/formname'):
node.text = str(FileDesc_obj.featureType)
for node in tree.findall('.//avlform/nondig/formname'):
node.text = str(FileDesc_obj.extension)
for node in tree.findall('.//avlform/digform/formname'):
node.text = str(float(os.path.getsize(File))/int(1024))+" KB"
for node in tree.findall('.//theme'):
node.text = str(FileDesc_obj.spatialReference.name +" ; EPSG: "+str(FileDesc_obj.spatialReference.factoryCode))
print node.text
projection_info=[]
Zone=FileDesc_obj.spatialReference.name
if "GCS" in str(FileDesc_obj.spatialReference.name):
projection_info=[FileDesc_obj.spatialReference.GCSName, FileDesc_obj.spatialReference.angularUnitName, FileDesc_obj.spatialReference.datumName, FileDesc_obj.spatialReference.spheroidName]
print "Geographic Coordinate system"
else:
projection_info=[FileDesc_obj.spatialReference.datumName, FileDesc_obj.spatialReference.spheroidName, FileDesc_obj.spatialReference.angularUnitName, Zone[Zone.rfind(zone)-3:]]
print "Projected Coordinate system"
x=0
for node in tree.findall('.//spdom'):
for node2 in node.findall('.//keyword'):
print node2.text
node2.text = str(projection_info[x])
print node2.text
x=x+1
tree.write(newMetaFile)
f = open(Generated_XMLs, 'a')
f.write(str(Count)+": "+File+"; "+newMetaFile+"; "+currentPath+"\n")
f.close()
# Create_xml(currentPath)
这是你的循环。在
最后你想说:
^{pr2}$这就结束了循环
或者你可以用这个(例子)
这将运行循环20次 哦,在第二次之后你需要缩进。在
您发布的代码在第二个else之后有一个缩进错误,但是没有循环,除非您迭代的列表之一非常非常大。这可能需要大量的复制操作(分析将有所帮助)。在
另外,在Python和英语中避免双重否定是可取的; 如果文件!=无: 如果文件:
必须添加一个break语句,这样它就脱离了循环。在
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