擅长:python、mysql、java
<p>最简单的方法是使用一周内经过的分钟数:</p>
<pre><code>def mins_in_week(day, hour, minute):
return day * 24 * 60 + hour * 60 + minute
if (mins_in_week(1, 16, 30) <
mins_in_week(TimeNow.weekday(), TimeNow.hour, TimeNow.minute) <
mins_in_week(3, 11, 45)):
....
</code></pre>