如何从PyQt5中的“动态生成”复选框中删除标签？

Question

因此，我有一个表格，其中有几个复选框，使用这些代码行动态生成：

chkBoxItem = QTableWidgetItem()
chkBoxItem.setTextAlignment(Qt.AlignHCenter)
chkBoxItem.setFlags(QtCore.Qt.ItemIsUserCheckable | QtCore.Qt.ItemIsEnabled)
chkBoxItem.setCheckState(QtCore.Qt.Unchecked) 
ui.columnTable.cellChanged.connect(self.checkColumnDataCheckbox)
ui.columnTable.setItem(i , 0, chkBoxItem)

我尝试过将其调整为一个较小的值，但不起作用：

^{pr2}$

似乎没有超过某个最小宽度和高度。
下面是它的样子：

基本上，我想删除这个文本标签，这样复选框就可以定位在单元格的中心

Answer 1

void QTableWidget::setCellWidget(int row, int column, QWidget *widget)

Sets the given widget to be displayed in the cell in the given row and column, passing the ownership of the widget to the table.

import sys
from PyQt5.QtGui     import *
from PyQt5.QtWidgets import *
from PyQt5.QtCore    import *

class Window(QWidget):
    def __init__(self, rows, columns):
        super().__init__()

        self.table = QTableWidget(rows, columns, self)

        for row in range(rows):
            widget   = QWidget()
            checkbox = QCheckBox()
            checkbox.setCheckState(Qt.Unchecked)
            layoutH = QHBoxLayout(widget)
            layoutH.addWidget(checkbox)
            layoutH.setAlignment(Qt.AlignCenter)
            layoutH.setContentsMargins(0, 0, 0, 0)

            self.table.setCellWidget(row, 0, widget)                  # <  
            self.table.setItem(row, 1, QTableWidgetItem(str(row)))

        self.button = QPushButton("Control selected QCheckBox")
        self.button.clicked.connect(self.ButtonClicked)

        layoutV     = QVBoxLayout(self)
        layoutV.addWidget(self.table)
        layoutV.addWidget(self.button)


    def ButtonClicked(self):
        checked_list = []
        for i in range(self.table.rowCount()):
            if self.table.cellWidget(i, 0).findChild(type(QCheckBox())).isChecked():
                checked_list.append(self.table.item(i, 1).text())
        print(checked_list)


if __name__ == '__main__':
    app = QApplication(sys.argv)
    window = Window(3, 3)
    window.resize(350, 300)
    window.show()
    sys.exit(app.exec_())