计算SSE时获取错误：'数字浮点数64'对象不是iterab

Question

我试图计算平方误差之和（SSE），代码如下所述

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def SSEadver(tv_train,radio_train,newsppr_train,y_train):
 y_train_predct = []
 sse_train = 0
 y_train_predct_srs = 0

# Calculating the predicted sales values on training data
 for i in range(0,len(tv_train)):
    y_train_predct.append(2.8769666223179353 + (0.04656457* tv_train.iloc[i])+ (0.17915812*(radio_train.iloc[i])) + (0.00345046*(newsppr_train.iloc[i])))

# ** Here I Convert  y_train_predct's type List to Series, but still it is showing type as list**
 y_train_predct_srs = pd.Series(y_train_predct)

# *** Due above converting not working here y_train_predct_srs.iloc[j]) is not working***   
# Now calculate SSE (sum of Squared Errors)
 for j in range (len(y_train)):
    sse_train +=  sum((y_train.iloc[j] - y_train_predct_srs.iloc[j])**2) 

return y_train_predct, y_train_predct_srs

sse_train = SSEadver(tv_train,radio_train,newsppr_train, y_train)

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运行此代码时，出现错误：

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^{pr2}$

为什么我得到这个错误？我使用的是python3.X.X

Answer 1

我看不到你所有的代码，但是看起来也一样

y_train.iloc或{}

不是名单，但事实上数字浮点数64. 您应该检查它们是否是绝对列表，然后再试一次。在