擅长:python、mysql、java
<p>您还可以使用<code>where</code>,如您所述</p>
<pre><code>condition = df.Conflict != 'Match Conflict'
df['Words'] = df.Words.where(condition, None)
Conflict Words
0 None {u'Sec': [u'level']}
1 None {u'Sec': [u'levels']}
2 None {u'Sec': [u'level']}
3 None {u'Und': [u'ba ']}
4 Match Conflict None
</code></pre>